To solve the expression \(2x + 4y \times 5\) and compare it with \(4x + 2y + 6\), we'll evaluate them step by step.

### Simplification:

1. **First Expression:**
   \[
   2x + 4y \times 5
   \]
   According to the order of operations (PEMDAS/BODMAS), you must first do the multiplication:
   \[
   = 2x + 20y
   \]
   So, the first expression simplifies to:
   \[
   2x + 20y
   \]

2. **Second Expression:**
   \[
   4x + 2y + 6
   \]
   This expression is already simplified and does not require any further calculation:
   \[
   4x + 2y + 6
   \]

### Final Comparison:
The two expressions are:
1. \(2x + 20y\)
2. \(4x + 2y + 6\)

These two expressions are not equal. You would need to equate them and solve for \(x\) and \(y\) if you want to find when they might be equal or to analyze the relationship between them.

Would you like to explore this further, or do you have another question?  

### Related Questions:
1. What are the values of \(x\) and \(y\) that would make these expressions equal?
2. How do you solve for \(x\) in a linear equation like \(2x + 20y = 4x + 2y + 6\)?
3. What are the different methods for simplifying algebraic expressions?
4. Can we graph these expressions and analyze their intersections?
5. What role does the distributive property play in simplifying algebraic expressions?

### Tip:
Always remember the order of operations (PEMDAS/BODMAS) when simplifying algebraic expressions to avoid mistakes.

Explore how to simplify and compare the linear expressions 2x + 4y × 5 and 4x + 2y + 6. This problem covers key algebraic concepts, including the order of operations and the distributive property. Suitable for students in Grades 6-8.

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