Math Problem Statement

2 + (3m - n)/5 - (1 - m)/2

Solution

The expression in the image is:

2+3mn51m22 + \frac{3m - n}{5} - \frac{1 - m}{2}

To simplify or manipulate this expression, we can:

  1. Find a common denominator between the fractions. The denominators are 5 and 2, so the least common denominator (LCD) is 10.
  2. Rewrite each term with the denominator 10: 2+2(3mn)105(1m)102 + \frac{2(3m - n)}{10} - \frac{5(1 - m)}{10} This becomes: 2+6m2n1055m102 + \frac{6m - 2n}{10} - \frac{5 - 5m}{10}
  3. Combine the fractions: 2+(6m2n)(55m)102 + \frac{(6m - 2n) - (5 - 5m)}{10} Simplify the numerator: 2+6m2n5+5m10=2+11m2n5102 + \frac{6m - 2n - 5 + 5m}{10} = 2 + \frac{11m - 2n - 5}{10}
  4. The simplified expression is: 2+11m2n5102 + \frac{11m - 2n - 5}{10} This can be rewritten as: 2010+11m2n510=20+11m2n510=11m2n+1510\frac{20}{10} + \frac{11m - 2n - 5}{10} = \frac{20 + 11m - 2n - 5}{10} = \frac{11m - 2n + 15}{10}

Thus, the final simplified expression is: 11m2n+1510\frac{11m - 2n + 15}{10}

Would you like more details on any step or have any questions?

Here are some related questions to expand on this:

  1. How can we solve this expression for mm?
  2. How can we solve this expression for nn?
  3. What happens if mm and nn are given specific values?
  4. How would you handle this expression if additional terms were added?
  5. Can this expression be factored further for certain values of mm and nn?

Tip: Always look for the least common denominator (LCD) when working with fractions—it helps to combine terms efficiently!

Ask a new question for Free

By Image

Drop file here or Click Here to upload

Math Problem Analysis

Mathematical Concepts

Algebra
Fractions
Simplification

Formulas

Least Common Denominator (LCD)
Fraction simplification formula

Theorems

Basic fraction operations

Suitable Grade Level

Grades 9-10