Math Problem Statement

2\left(\dfrac{1}{5}m-\dfrac{2}{5}\right)+\dfrac{3}5

Solution

Let's simplify the given expression step by step:

2(15m25)+352\left(\dfrac{1}{5}m - \dfrac{2}{5}\right) + \dfrac{3}{5}

Step 1: Distribute the 2 across the terms inside the parentheses.

We multiply 22 by both 15m\dfrac{1}{5}m and 25\dfrac{2}{5}:

215m=25m2 \cdot \dfrac{1}{5}m = \dfrac{2}{5}m 225=452 \cdot \dfrac{2}{5} = \dfrac{4}{5}

Now, the expression becomes:

25m45+35\dfrac{2}{5}m - \dfrac{4}{5} + \dfrac{3}{5}

Step 2: Combine like terms.

The constants 45-\dfrac{4}{5} and 35\dfrac{3}{5} are like terms, so we combine them:

45+35=15-\dfrac{4}{5} + \dfrac{3}{5} = -\dfrac{1}{5}

Now, the simplified expression is:

25m15\dfrac{2}{5}m - \dfrac{1}{5}

Final Answer:

The simplified form of the expression is:

25m15\dfrac{2}{5}m - \dfrac{1}{5}

Would you like a more detailed explanation of any step or have any other questions?

Here are 5 related questions you might find helpful:

  1. How do you factor out common terms from algebraic expressions?
  2. Can you solve an equation if 25m15=0\dfrac{2}{5}m - \dfrac{1}{5} = 0?
  3. How do you handle fractions when solving algebraic equations?
  4. What are the general steps for simplifying expressions involving distribution?
  5. How do you solve for a variable when fractions are involved?

Tip: When simplifying, always combine like terms (such as constants or variables) to make your expression as simple as possible.

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Math Problem Analysis

Mathematical Concepts

Algebra
Simplifying Expressions
Distribution
Combining Like Terms

Formulas

Distribution: a(b + c) = ab + ac
Combining like terms: ax + bx = (a + b)x

Theorems

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Suitable Grade Level

Grades 6-8