Math Problem Statement

Write the expression \( \sin^2 \theta (1 + \cot^2 \theta) \) in terms of sine and cosine, and simplify so that no quotients appear in the final expression.

Solution

To solve this problem, let's analyze the expression given:

Expression to simplify:
sin2θ(1+cot2θ)\sin^2 \theta (1 + \cot^2 \theta)

Step-by-Step Solution

  1. Rewrite cot2θ\cot^2 \theta in terms of sine and cosine: cotθ=cosθsinθ\cot \theta = \frac{\cos \theta}{\sin \theta} So, cot2θ=cos2θsin2θ\cot^2 \theta = \frac{\cos^2 \theta}{\sin^2 \theta}

  2. Substitute cot2θ\cot^2 \theta into the expression: sin2θ(1+cos2θsin2θ)\sin^2 \theta \left(1 + \frac{\cos^2 \theta}{\sin^2 \theta}\right)

  3. Simplify the expression inside the parentheses: 1+cos2θsin2θ=sin2θ+cos2θsin2θ1 + \frac{\cos^2 \theta}{\sin^2 \theta} = \frac{\sin^2 \theta + \cos^2 \theta}{\sin^2 \theta}

    Using the Pythagorean identity sin2θ+cos2θ=1\sin^2 \theta + \cos^2 \theta = 1, we get: 1+cos2θsin2θ=1sin2θ1 + \frac{\cos^2 \theta}{\sin^2 \theta} = \frac{1}{\sin^2 \theta}

  4. Rewrite the entire expression: sin2θ1sin2θ\sin^2 \theta \cdot \frac{1}{\sin^2 \theta}

  5. Simplify by canceling sin2θ\sin^2 \theta: sin2θ1sin2θ=1\sin^2 \theta \cdot \frac{1}{\sin^2 \theta} = 1

Conclusion

The expression simplifies to 11.

Answer

The correct answer is:

  • C. 11

Would you like further details on any specific steps?


Here are five questions for practice:

  1. What is the Pythagorean identity involving sin2θ\sin^2 \theta and cos2θ\cos^2 \theta?
  2. How can you express cot2θ\cot^2 \theta in terms of sinθ\sin \theta and cosθ\cos \theta?
  3. Why does sin2θ1sin2θ\sin^2 \theta \cdot \frac{1}{\sin^2 \theta} simplify to 11?
  4. What other trigonometric identities can help simplify complex expressions?
  5. How would the solution change if the original expression were sin2θ(1cot2θ)\sin^2 \theta (1 - \cot^2 \theta)?

Tip:

When simplifying trigonometric expressions, look for identities that can help convert terms into sine and cosine, as this often makes simplification easier.

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Math Problem Analysis

Mathematical Concepts

Trigonometry
Trigonometric Identities

Formulas

Pythagorean identity: \( \sin^2 \theta + \cos^2 \theta = 1 \)
Cotangent identity: \( \cot \theta = \frac{\cos \theta}{\sin \theta} \)

Theorems

Pythagorean Identity

Suitable Grade Level

Grades 10-12