Math Problem Statement

Write the following in terms of sin θ and cos θ; then simplify if possible: sin θ cot θ + 4 cos θ

Solution

The problem in the image asks to "Write the following in terms of sinθ\sin \theta and cosθ\cos \theta; then simplify if possible":

sinθcotθ+4cosθ\sin \theta \cot \theta + 4 \cos \theta

Let's break this down:

Step 1: Express cotθ\cot \theta in terms of sinθ\sin \theta and cosθ\cos \theta.

We know that: cotθ=cosθsinθ\cot \theta = \frac{\cos \theta}{\sin \theta}

Step 2: Substitute this into the original expression.

sinθcotθ+4cosθ=sinθcosθsinθ+4cosθ\sin \theta \cdot \cot \theta + 4 \cos \theta = \sin \theta \cdot \frac{\cos \theta}{\sin \theta} + 4 \cos \theta

Step 3: Simplify the expression.

The sinθ\sin \theta in the numerator and denominator cancels out in the first term: cosθ+4cosθ\cos \theta + 4 \cos \theta

Step 4: Combine like terms.

cosθ+4cosθ=5cosθ\cos \theta + 4 \cos \theta = 5 \cos \theta

Thus, the simplified expression is: 5cosθ5 \cos \theta

Would you like more details or explanations on any part of this process?

Relative Questions:

  1. What is the cotangent function and how is it related to sine and cosine?
  2. How do we simplify trigonometric expressions involving multiple functions?
  3. Can we always cancel terms in trigonometric identities like we did with sinθ\sin \theta?
  4. What happens if sinθ=0\sin \theta = 0 in this particular problem?
  5. How do we apply trigonometric identities in more complex equations?

Tip:

Always express trigonometric functions in terms of sine and cosine when simplifying, as this often leads to easier cancellation and simplification.

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Math Problem Analysis

Mathematical Concepts

Trigonometry
Simplification of Trigonometric Expressions

Formulas

cot θ = cos θ / sin θ

Theorems

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Suitable Grade Level

Grades 10-12