Math Problem Statement

1/sin(theta) - 1/cos(theta)

Solution

The expression you provided is:

1sin(θ)1cos(θ)\frac{1}{\sin(\theta)} - \frac{1}{\cos(\theta)}

We can simplify this by finding a common denominator:

  1. The common denominator between sin(θ)\sin(\theta) and cos(θ)\cos(\theta) is sin(θ)cos(θ)\sin(\theta)\cos(\theta).

  2. Rewrite each term using the common denominator:

cos(θ)sin(θ)cos(θ)sin(θ)sin(θ)cos(θ)\frac{\cos(\theta)}{\sin(\theta)\cos(\theta)} - \frac{\sin(\theta)}{\sin(\theta)\cos(\theta)}

  1. Combine the two fractions:

cos(θ)sin(θ)sin(θ)cos(θ)\frac{\cos(\theta) - \sin(\theta)}{\sin(\theta)\cos(\theta)}

So, the simplified form of the expression is:

cos(θ)sin(θ)sin(θ)cos(θ)\frac{\cos(\theta) - \sin(\theta)}{\sin(\theta)\cos(\theta)}

Would you like further details on trigonometric simplifications, or any other questions?

Related Questions:

  1. What happens if θ=45\theta = 45^\circ in this expression?
  2. How do we simplify 1sin(θ)+1cos(θ)\frac{1}{\sin(\theta)} + \frac{1}{\cos(\theta)}?
  3. Can we express sin(θ)\sin(\theta) and cos(θ)\cos(\theta) in terms of other trigonometric functions?
  4. How do we handle this expression if θ\theta is an unknown angle?
  5. What real-world problems involve these trigonometric expressions?

Tip:

Always consider factoring or using identities like Pythagoras’ theorem for trigonometric simplifications.

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Math Problem Analysis

Mathematical Concepts

Trigonometry
Fractions
Simplification

Formulas

Reciprocal identities: 1/sin(θ) = csc(θ), 1/cos(θ) = sec(θ)

Theorems

Trigonometric identities
Common denominator method

Suitable Grade Level

Grades 10-12