To simplify the expression \((t + 1) \cdot 3\), we distribute the \(3\) to both terms inside the parentheses:

\[
(t + 1) \cdot 3 = t \cdot 3 + 1 \cdot 3
\]

Now, we perform the multiplication for each term:

1. \(t \cdot 3 = 3t\)
2. \(1 \cdot 3 = 3\)

Combining these, the simplified expression is:

\[
3t + 3
\]

Thus, the simplified form of \((t + 1) \cdot 3\) is:

\[
3t + 3
\]

Would you like more details or have any questions?

Here are some related questions you might find interesting:

1. How do you distribute a constant across a binomial?
2. What are the steps to simplify expressions with multiple terms?
3. How can you factor the expression \(3t + 3\)?
4. What is the difference between distributing and factoring in algebra?
5. How does the distributive property apply to more complex expressions?

**Tip:** Remember, when distributing a constant over a binomial, multiply the constant by each term inside the parentheses individually.

Learn how to simplify the expression (t + 1) * 3 using the distributive property. Step-by-step explanation with examples showing how to distribute a constant over a binomial. Suitable for students in Grades 6-8.

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