(t + 1) ∙ 3 solve this but explain it with step by step solving the equation

Sure! Let's solve the expression \((t + 1) \cdot 3\) step by step.

### Step 1: Understand the Expression
The expression \((t + 1) \cdot 3\) involves multiplying a binomial \((t + 1)\) by a constant \(3\).

### Step 2: Distribute the Constant
Use the distributive property, which states that \(a \cdot (b + c) = a \cdot b + a \cdot c\).

In this case, \(a = 3\), \(b = t\), and \(c = 1\). We distribute \(3\) to both terms inside the parentheses:

\[
(t + 1) \cdot 3 = 3 \cdot t + 3 \cdot 1
\]

### Step 3: Perform the Multiplication
Now, multiply \(3\) by each term:

\[
3 \cdot t = 3t
\]
\[
3 \cdot 1 = 3
\]

### Step 4: Combine the Results
After multiplying, combine the results:

\[
3t + 3
\]

So, the final simplified expression is:

\[
3t + 3
\]

This is the expanded form of the original expression.

Would you like more details or have any questions?

Here are 5 related questions:
1. How would you solve \((2t + 3) \cdot 4\) step by step?
2. Can you solve and explain \((t - 2) \cdot 5\) in detail?
3. How do you apply the distributive property in the expression \(4(t + 6)\)?
4. What is the process for simplifying \((3t + 1) \cdot 2\)?
5. How would you factor the expression \(3t + 3\) back into its original form?

**Tip:** When solving algebraic expressions, always start by applying the distributive property if there are terms in parentheses.

Learn how to solve the expression (t + 1) * 3 with a detailed step-by-step solution. This problem involves applying the distributive property in algebra. Suitable for students in Grades 7-9.

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