Simplify the expression to a, plus, b, i*a*+*bi* form:

minus, square root of, 36, end square root, minus, square root of, minus, 9, end square root, minus, square root of, 1, end square root, minus, square root of, minus, 64, end square root

Let's simplify the given expression step by step.

The expression is:

\[
-\sqrt{36} - \sqrt{-9} - \sqrt{1} - \sqrt{-64}
\]

### Step 1: Simplify each square root term.

1. \(\sqrt{36} = 6\), so \( -\sqrt{36} = -6\).
2. \(\sqrt{-9}\) involves the square root of a negative number, which can be written as \( \sqrt{-9} = \sqrt{9} \times \sqrt{-1} = 3i \), so \( -\sqrt{-9} = -3i \).
3. \(\sqrt{1} = 1\), so \( -\sqrt{1} = -1\).
4. \(\sqrt{-64}\) can be written as \( \sqrt{64} \times \sqrt{-1} = 8i \), so \( -\sqrt{-64} = -8i \).

### Step 2: Combine the simplified terms.

Now, the expression becomes:

\[
-6 - 3i - 1 - 8i
\]

### Step 3: Group the real and imaginary terms.

Combine the real parts and the imaginary parts:

\[
(-6 - 1) + (-3i - 8i) = -7 - 11i
\]

### Final Answer:

The expression simplified to \( a + bi \) form is:

\[
\boxed{-7 - 11i}
\]

Would you like details on any step or have any further questions? Here are some related questions:

1. How do you simplify complex numbers involving square roots of negative numbers?
2. What is the significance of the imaginary unit \(i\) in mathematics?
3. How do you add or subtract complex numbers?
4. What are some real-life applications of complex numbers?
5. How do you multiply and divide complex numbers?

**Tip:** Always remember that the square root of a negative number introduces the imaginary unit \(i\), where \(i = \sqrt{-1}\).

Explore how to simplify an expression involving square roots of negative numbers and complex numbers. Step-by-step solution provided with detailed explanations and examples. Suitable for advanced high school students and those studying complex numbers in mathematics.

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