Math Problem Statement

Find the real-number root.

Find the real-number root of √-3.24.

Solution

The expression you provided is the square root of a negative number, 3.24\sqrt{-3.24}.

In the real number system, there is no real number whose square is negative, so this expression does not have a real number solution. However, in the system of complex numbers, the square root of a negative number can be expressed in terms of imaginary numbers.

We can rewrite the expression as:

3.24=1×3.24=i×3.24\sqrt{-3.24} = \sqrt{-1} \times \sqrt{3.24} = i \times \sqrt{3.24}

Since 3.24=1.8\sqrt{3.24} = 1.8, we have:

3.24=1.8i\sqrt{-3.24} = 1.8i

Thus, the solution in the complex number system is 1.8i1.8i.

Would you like more details or have any other questions?

Here are 5 related questions to explore this topic further:

  1. What are imaginary numbers, and how are they used in mathematics?
  2. Can all negative square roots be expressed as complex numbers?
  3. How do we add and multiply complex numbers?
  4. What is the significance of the imaginary unit ii in various fields of science?
  5. How do we find the square root of a complex number?

Tip: The imaginary unit ii is defined as the square root of 1-1, and it's used extensively in engineering, physics, and other fields to handle problems involving oscillations, waves, and more.

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Math Problem Analysis

Mathematical Concepts

Complex Numbers
Imaginary Numbers
Square Roots

Formulas

√-a = i√a
i = √-1

Theorems

Complex Number Theory

Suitable Grade Level

High School (Grades 9-12)