Math Problem Statement

Pro a ∈ N upravte výraz a vyjádřete jej ve tvaru odmocniny o základu a. a^(1/2) : 6√a =

Solution

The problem asks to express the given expression in terms of roots with a base of aa, where aNa \in \mathbb{N}.

The expression provided is:

a12:a6a^{\frac{1}{2}} : \sqrt[6]{a}

To solve this, let’s analyze and simplify step by step.

  1. Rewrite a12a^{\frac{1}{2}}: This is already in the form of a power, and it represents the square root of aa: a12=aa^{\frac{1}{2}} = \sqrt{a}

  2. Rewrite a6\sqrt[6]{a}: This is the sixth root of aa, which can be written as a power: a6=a16\sqrt[6]{a} = a^{\frac{1}{6}}

  3. Formulate the division: Now, we have a12:a16=a1216a^{\frac{1}{2}} : a^{\frac{1}{6}} = a^{\frac{1}{2} - \frac{1}{6}}

  4. Simplify the exponent: 1216=316=26=13\frac{1}{2} - \frac{1}{6} = \frac{3 - 1}{6} = \frac{2}{6} = \frac{1}{3}

Thus, the expression simplifies to:

a13a^{\frac{1}{3}}

  1. Express in root form: a13a^{\frac{1}{3}} can be rewritten as the cube root of aa: a13=a3a^{\frac{1}{3}} = \sqrt[3]{a}

Final Answer

[ a^{\frac{1}{2}} : \sqrt[6]{a} = \sqrt[3]{a} ]

Would you like further details on any part of this solution, or do you have any questions?

Here are some related questions for further exploration:

  1. What are the rules for simplifying expressions with roots and powers?
  2. How can we express higher roots, like the sixth root, in terms of fractional exponents?
  3. What other methods can be used to simplify expressions involving roots and powers?
  4. How does changing the base of the exponent affect the result of a similar expression?
  5. What practical applications involve simplifying expressions with roots and fractional exponents?

Tip: When simplifying expressions with powers and roots, remember that division of terms with the same base allows you to subtract the exponents directly.

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Math Problem Analysis

Mathematical Concepts

Algebra
Exponentiation
Roots

Formulas

a^(1/2) = √a
a^(1/6) = 6√a
a^(m) / a^(n) = a^(m - n)

Theorems

Laws of Exponents

Suitable Grade Level

Grades 10-12