The given expression from the image is:

$\frac{(2^3)^2 \cdot 3^2}{3^3 \cdot 2^4}$

Let's simplify this step by step:

1. Simplify the terms: $(2^3)^2 = 2^{3 \cdot 2} = 2^6$ So the expression becomes: $\frac{2^6 \cdot 3^2}{3^3 \cdot 2^4}$

2. Now, apply the properties of exponents (i.e., subtract exponents when dividing terms with the same base):

   • For $2$: $\frac{2^6}{2^4} = 2^{6-4} = 2^2$
   • For $3$: $\frac{3^2}{3^3} = 3^{2-3} = 3^{-1}$

3. The expression now becomes: $2^2 \cdot 3^{-1}$ Which is: $\frac{2^2}{3} = \frac{4}{3}$

Thus, the simplified result of the given expression is:

$\frac{4}{3}$

Would you like more details on any part of this solution? Here are 5 related questions for further exploration:

1. How do exponent rules work when multiplying or dividing terms with the same