Math Problem Statement

[(2square)cube x 3 raised to power 6] x 5 raised to power 6

Solution

The expression you've provided is:

[(22)3×36]×56[(2^2)^3 \times 3^6] \times 5^6

Let's break it down step by step:

  1. Start with the first part: (22)3(2^2)^3:

    • First, calculate 222^2, which is 4.
    • Then raise that result to the power of 3: (22)3=43=64(2^2)^3 = 4^3 = 64.
  2. Next, multiply that by 363^6:

    • 36=7293^6 = 729.

So, the expression so far is:

64×729=4665664 \times 729 = 46656

  1. Now, multiply by 565^6:
    • 56=156255^6 = 15625.

Finally, multiply 46656×1562546656 \times 15625:

46656×15625=72843750046656 \times 15625 = 728437500

Final answer:

728437500728437500

Would you like a more detailed explanation, or do you have any further questions about this?

Here are some related questions:

  1. How would you simplify expressions with multiple exponents like this one?
  2. What is the general rule for exponents when you have nested powers (like (am)n(a^m)^n)?
  3. How can you quickly calculate powers of numbers like 363^6 and 565^6?
  4. What would happen if the bases of the powers in the expression were negative numbers instead?
  5. How do you estimate large numbers when dealing with exponents?

Tip: When dealing with exponents, remember that (am)n=am×n(a^m)^n = a^{m \times n}. This can save you time and help simplify the expression more quickly.

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Math Problem Analysis

Mathematical Concepts

Exponents
Powers
Multiplication of Exponents

Formulas

(a^m)^n = a^(m*n)
a^b * a^c = a^(b+c)

Theorems

Exponentiation rules
Power of a power rule

Suitable Grade Level

Grades 7-9