The expression in the image represents a Boolean function that can be solved using the POS (Product of Sums) method. Here’s how to approach solving this step-by-step:

Given Expression:

$(A + B + C)(A + \overline{B} + C)(\overline{A} + B + C)(\overline{A} + \overline{B} + C)(A + B + \overline{C})$

The POS (Product of Sums) method requires you to:

1. Treat each group of terms within parentheses as a sum (OR) term.
2. The overall function is a product (AND) of these terms.

Steps to Simplify:

1. Interpret Each Term: Each term inside the parentheses is already in sum (OR) form:

   • $(A + B + C)$
   • $(A + \overline{B} + C)$
   • $(\overline{A} + B + C)$
   • $(\overline{A} + \overline{B} + C)$
   • $(A + B + \overline{C})$

2. Combine the Terms: The full Boolean expression is the AND of all the terms: $(A + B + C) \cdot (A + \overline{B} + C) \cdot (\overline{A} + B + C) \cdot (\overline{A} + \overline{B} + C) \cdot (A + B + \overline{C})$

3. Simplify (if needed):

   • Analyze whether some terms make others redundant. For example, if $C$ is present in every term, the resulting expression might depend only on the remaining variables.
   • Use Boolean algebra rules like:
     • $X + \overline{X} = 1$ (Elimination rule)
     • $X \cdot 1 = X$ (Identity)
     • $X + 1 = 1$ (Absorption)

Observations:

• $C$ is included in all the terms, so $C$ will always evaluate to $1$, making it irrelevant to further simplifications in POS form.
• The remaining terms focus on the combinations of $A, B,$ and their complements.

If you'd like, I can simplify further or explain each Boolean algebra step in detail. Let me know!