The image shows a triangle with sides labeled as expressions in terms of $y$. The sides of the triangle are:

• $3y + 5$
• $6y$
• $y - 4$

To find the perimeter of the triangle, we simply add these expressions together:

$\text{Perimeter} = (3y + 5) + 6y + (y - 4)$

Now, let's simplify this expression by combining like terms:

$\text{Perimeter} = 3y + 6y + y + 5 - 4$

$\text{Perimeter} = (3y + 6y + y) + (5 - 4)$

$\text{Perimeter} = 10y + 1$

Thus, the perimeter of the triangle as a simplified expression is:

$\boxed{10y + 1}$

Would you like further details or explanations?

Here are five related questions to expand your understanding:

1. How would the perimeter change if one side were doubled?
2. How do you find the perimeter of a triangle if the sides are given as fractions?
3. Can you write the expression for the area of this triangle using Heron's formula?
4. What would the perimeter be if $y = 2$?
5. How do you find the perimeter of a triangle with sides that contain square roots?

Tip: Always combine like terms when simplifying algebraic expressions to avoid mistakes.