Let's break down the information and set up equations based on the data provided.

Define:

• Let $A$, $R$, and $M$ be the sets of customers who bought from Ajay, Raj, and Mohit, respectively.

Given information:

1. Total customers in the market: $|A \cup R \cup M| = 600$.
2. Customers who bought from Ajay: $|A| = 50\% \times 600 = 300$.
3. Customers who bought from Raj: $|R| = 55\% \times 600 = 330$.
4. Customers who bought from Mohit: $|M| = 45\% \times 600 = 270$.
5. Customers who bought from all three stalls: $|A \cap R \cap M| = 20\% \times 300 = 60$.
6. Customers who bought from any two stalls: $|A \cap R| + |R \cap M| + |M \cap A| - 2 |A \cap R \cap M| = 190$.
7. Customers who only bought from Ajay are 40 more than those who only bought from Raj.
8. Customers who bought only from Ajay and Raj: $|A \cap R| - |A \cap R \cap M| = 80$.

Let's solve step-by-step.

Step 1: Set up the information in equations

Let:

• $|A \cap R| = x$
• $|R \cap M| = y$
• $|M \cap A| = z$

From information given:

1. $|A \cap R \cap M| = 60$.
2. $x + y + z - 2 \times 60 = 190$.
   • Simplifying, $x + y + z = 310$.
3. $x - 60 = 80$, so $x = 140$.

Step 2: Substitute values

Using $x = 140$:

1. $140 + y + z = 310$ gives $y + z = 170$.

Step 3: Use the remaining information

Let:

• Customers who only bought from Ajay be $a$,
• Customers who only bought from Raj be $r$,
• Customers who only bought from Mohit be $m$.

We know:

1. $a = r + 40$.
2. From the inclusion-exclusion principle: $|A \cup R \cup M| = a + r + m + x + y + z + 60 = 600$ Substituting known values gives: $a + r + m + 140 + 170 + 60 = 600$ Simplifying, $a + r + m = 230$

Step 4: Solve for individual values of $a$, $r$, and $m$

Using $a = r + 40$:

1. Substitute $a = r + 40$ in $a + r + m = 230$: $(r + 40) + r + m = 230$ $2r + m = 190$

Now we need further equations or assumptions to solve fully for each