Math Problem Statement

Let A be the set of the first 8 even numbers and B be the set of the first 8 multiples of 3. i) Write A and B in Roster Method. ii) Verify that A∩B = B∩A. Find |z/ž| for z = 3 - 7i and ž being the conjugate of z. For f(x) = 5x + 1 and g(x) = x^2, find (f o g)(x) and (g o f)(x). Solve the quadratic equation 2x^2 - 4x + 1 = 0.

Solution

Let's work through each question in detail.

Question 1

Let:

  • AA: The set of the first 8 even numbers
  • BB: The set of the first 8 multiples of 3
  1. Write AA and BB in Roster Method:

    • The first 8 even numbers are: 2,4,6,8,10,12,14,162, 4, 6, 8, 10, 12, 14, 16

    • So, A={2,4,6,8,10,12,14,16}A = \{ 2, 4, 6, 8, 10, 12, 14, 16 \}

    • The first 8 multiples of 3 are: 3,6,9,12,15,18,21,243, 6, 9, 12, 15, 18, 21, 24

    • So, B={3,6,9,12,15,18,21,24}B = \{ 3, 6, 9, 12, 15, 18, 21, 24 \}

  2. Verify that AB=BAA \cap B = B \cap A:

    • The intersection of AA and BB (common elements) is {6,12}\{ 6, 12 \}
    • So, AB={6,12}A \cap B = \{ 6, 12 \} and BA={6,12}B \cap A = \{ 6, 12 \}
    • Therefore, AB=BAA \cap B = B \cap A.

Question 2

Let z=37iz = 3 - 7i. Find zzˉ\left| \frac{z}{\bar{z}} \right|, where zˉ\bar{z} is the complex conjugate of zz.

  1. The complex conjugate of z=37iz = 3 - 7i is zˉ=3+7i\bar{z} = 3 + 7i.
  2. Calculate zzˉ\frac{z}{\bar{z}}: zzˉ=37i3+7i\frac{z}{\bar{z}} = \frac{3 - 7i}{3 + 7i} Multiply the numerator and denominator by the conjugate of the denominator: (37i)(37i)(3+7i)(37i)=942i+49i2949i2=942i499+49=4042i58=20292129i\frac{(3 - 7i)(3 - 7i)}{(3 + 7i)(3 - 7i)} = \frac{9 - 42i + 49i^2}{9 - 49i^2} = \frac{9 - 42i - 49}{9 + 49} = \frac{-40 - 42i}{58} = -\frac{20}{29} - \frac{21}{29}i
  3. Calculate the magnitude: zzˉ=(2029)2+(2129)2=400841+441841=841841=1\left| \frac{z}{\bar{z}} \right| = \sqrt{\left( -\frac{20}{29} \right)^2 + \left( -\frac{21}{29} \right)^2} = \sqrt{\frac{400}{841} + \frac{441}{841}} = \sqrt{\frac{841}{841}} = 1 So, zzˉ=1\left| \frac{z}{\bar{z}} \right| = 1.

Question 3

Let f(x)=5x+1f(x) = 5x + 1 and g(x)=x2g(x) = x^2. Find the composite functions (fg)(x)(f \circ g)(x) and (gf)(x)(g \circ f)(x).

  1. Find (fg)(x)(f \circ g)(x):

    • (fg)(x)=f(g(x))=f(x2)=5(x2)+1=5x2+1(f \circ g)(x) = f(g(x)) = f(x^2) = 5(x^2) + 1 = 5x^2 + 1
  2. Find (gf)(x)(g \circ f)(x):

    • (gf)(x)=g(f(x))=g(5x+1)=(5x+1)2=25x2+10x+1(g \circ f)(x) = g(f(x)) = g(5x + 1) = (5x + 1)^2 = 25x^2 + 10x + 1

Question 4

Solve the quadratic equation 2x24x+1=02x^2 - 4x + 1 = 0.

  1. Using the quadratic formula: x=(4)±(4)242122x = \frac{-(-4) \pm \sqrt{(-4)^2 - 4 \cdot 2 \cdot 1}}{2 \cdot 2} Simplify inside the square root: x=4±1684=4±84=4±224=1±22x = \frac{4 \pm \sqrt{16 - 8}}{4} = \frac{4 \pm \sqrt{8}}{4} = \frac{4 \pm 2\sqrt{2}}{4} = 1 \pm \frac{\sqrt{2}}{2} So, the solutions are: x=1+22andx=122x = 1 + \frac{\sqrt{2}}{2} \quad \text{and} \quad x = 1 - \frac{\sqrt{2}}{2}

Would you like further details or explanations on any specific question?

Here are five related questions to explore further:

  1. How do you find the union of two sets, like ABA \cup B, and how is it different from the intersection?
  2. How can you generalize the concept of complex conjugates for any complex number?
  3. What happens when you reverse the order in composite functions? Does it always yield a different result?
  4. How can we solve a quadratic equation by completing the square?
  5. What are some practical applications of complex numbers in real-world problems?

Tip: For composite functions, remember that (fg)(x)(f \circ g)(x) means applying gg first, then ff. This order matters and often leads to different results from (gf)(x)(g \circ f)(x).

Ask a new question for Free

By Image

Drop file here or Click Here to upload

Math Problem Analysis

Mathematical Concepts

Set Theory
Complex Numbers
Composite Functions
Quadratic Equations

Formulas

Intersection of Sets: A ∩ B
Magnitude of a Complex Number: |z| = √(a^2 + b^2) for z = a + bi
Composite Function: (f o g)(x) = f(g(x))
Quadratic Formula: x = (-b ± √(b^2 - 4ac)) / 2a

Theorems

Commutative Property of Set Intersection: A ∩ B = B ∩ A
Properties of Complex Conjugates
Quadratic Formula

Suitable Grade Level

Grade 10-12