Math Problem Statement

Determine whether the series ∑(-1)^n(6n)/√(25n^4 - 1) from n=1 to ∞ is absolutely convergent, conditionally convergent, or divergent.

Solution

This exercise is about determining whether the given series is absolutely convergent, conditionally convergent, or divergent. Here’s a step-by-step breakdown of the solution:

Problem Analysis

The series is: n=1(1)n(6n)25n41\sum_{n=1}^{\infty} \frac{(-1)^n (6n)}{\sqrt{25n^4 - 1}}

It’s an alternating series (indicated by the factor (1)n(-1)^n), so we'll evaluate both absolute and conditional convergence.

Part 1: Testing an\sum |a_n|

Absolute Convergence

To determine if the series is absolutely convergent, we consider the absolute value of ana_n: an=6n25n41|a_n| = \frac{6n}{\sqrt{25n^4 - 1}}

We use the Limit Comparison Test with a simpler comparison series of the form cnp\frac{c}{n^p}.

  1. Choice of Comparison Series: The leading term in the denominator, 25n4=5n2\sqrt{25n^4} = 5n^2, suggests comparing an|a_n| with 65n\frac{6}{5n}.

  2. Calculations:

    • The constant c=65c = \frac{6}{5} and p=1p = 1.
    • Using the limit comparison, we find: limnanbn=1\lim_{n \to \infty} \frac{|a_n|}{b_n} = 1
    • Since bn=cn\sum b_n = \sum \frac{c}{n} diverges (harmonic series), an\sum |a_n| also diverges.

This confirms that the series is not absolutely convergent.

Part 2: Conclusion on Convergence

Since an\sum |a_n| diverges, we now check if the series an\sum a_n converges conditionally.

Conditional Convergence

The series an\sum a_n is an alternating series, and we can apply the Alternating Series Test (Leibniz’s test).

  1. Conditions of the Alternating Series Test:
    • Monotonicity: {bn}=6n25n41\{b_n\} = \frac{6n}{\sqrt{25n^4 - 1}} is ultimately decreasing for n>6/5n > 6/5.
    • Limit Condition: limnbn=0\lim_{n \to \infty} b_n = 0.

Since both conditions are satisfied, the series an\sum a_n converges conditionally.

Final Answer

  • The series an\sum a_n is conditionally convergent.

Would you like further details on any specific part of this solution? Here are related questions that might be useful:

  1. How does the Limit Comparison Test work in determining convergence?
  2. Why does the harmonic series diverge, and how is it applied in comparison?
  3. What is the Alternating Series Test, and why is it useful here?
  4. How do we determine if a series is absolutely convergent?
  5. What are examples of other conditionally convergent series?

Tip: For alternating series, always verify if the terms decrease and approach zero, as this is critical for conditional convergence.

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Math Problem Analysis

Mathematical Concepts

Series Convergence
Absolute Convergence
Conditional Convergence
Limit Comparison Test
Alternating Series Test

Formulas

Absolute value of a series term |a_n| = 6n/√(25n^4 - 1)
Comparison series b_n = c/(n^p) where c = 6/5 and p = 1
Alternating Series Test criteria

Theorems

Limit Comparison Test
Alternating Series Test

Suitable Grade Level

College