Math Problem Statement

is the series from 1 to infinity of ( 6x)/(sqrt(25x^4-1)) convergent? mention tests used

Solution

To determine the convergence of the series

n=16x25x41\sum_{n=1}^{\infty} \frac{6x}{\sqrt{25x^4 - 1}}

we need to examine the behavior of the general term:

an=6x25x41.a_n = \frac{6x}{\sqrt{25x^4 - 1}}.

Given that xx does not vary with nn, the term ana_n is a constant and does not depend on nn. Therefore, it cannot converge to zero as nn \to \infty (unless x=0x = 0, in which case the whole series would trivially be zero).

1. Divergence Test (or nth-term Test for Divergence)

For a series an\sum a_n to converge, a necessary condition is that limnan=0\lim_{n \to \infty} a_n = 0. Since an=6x25x41a_n = \frac{6x}{\sqrt{25x^4 - 1}} is constant (for any nonzero xx), it does not approach zero as nn \to \infty.

Hence, by the Divergence Test, the series diverges for all x0x \neq 0.

Conclusion

Since the Divergence Test shows that the terms do not approach zero, the series n=16x25x41\sum_{n=1}^{\infty} \frac{6x}{\sqrt{25x^4 - 1}} diverges for any nonzero xx.

Would you like more details or have any questions?


  1. What is the Divergence Test and why is it used in series analysis?
  2. How do we apply other convergence tests, like the Ratio Test, to more complex series?
  3. What happens if ana_n is not constant but depends on nn?
  4. How would a term that does approach zero affect the series' convergence?
  5. Can other tests be applied to this specific series to further verify divergence?

Tip: The Divergence Test is a quick first step in testing for convergence—it helps determine if further testing is even necessary!

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Math Problem Analysis

Mathematical Concepts

Series Convergence
Infinite Series
Divergence Test

Formulas

a_n = 6x / sqrt(25x^4 - 1)

Theorems

Divergence Test (or nth-term Test for Divergence)

Suitable Grade Level

College