Math Problem Statement
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Solution
The problem you uploaded states the following:
Let be a sequence of integers. Show that there exist integers and with such that the sum is a multiple of .
Solution Outline:
This is a classic problem in number theory, often solved using the pigeonhole principle.
Step-by-Step Solution:
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Partial Sums: Define partial sums as: These partial sums represent the sum of the first elements of the sequence. Now consider the sum for , which is the sum of elements from to .
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Modulo : Since we are interested in finding a sum that is a multiple of , we look at these sums modulo . Define the values: Notice that there are sums in total ( to ) and only possible remainders when divided by (which are ).
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Pigeonhole Principle: By the pigeonhole principle, among the values , at least two of them must have the same value modulo . Suppose for some .
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Conclude the Solution: If , then: which means that the sum of the elements from to , i.e., is divisible by .
Therefore, we have shown that there exist integers and such that the sum of the sequence from to is a multiple of , as required.
Would you like any further clarifications or detailed examples?
Additional Related Questions:
- How does the pigeonhole principle work in problems involving modulo arithmetic?
- Can you generalize this result to sequences where the number of terms exceeds ?
- What are some other common applications of the pigeonhole principle in number theory?
- Can this problem be solved using any other mathematical technique like induction?
- What changes if the sequence contains negative numbers?
Tip: When working with modular arithmetic problems, always try to reduce sums or sequences modulo the divisor to simplify the calculations.
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Math Problem Analysis
Mathematical Concepts
Number Theory
Modular Arithmetic
Pigeonhole Principle
Formulas
S_k = ∑_(i=1)^k a_i
S_k ≡ S_j (mod n)
Theorems
Pigeonhole Principle
Suitable Grade Level
Grades 11-12, College
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