Math Problem Statement

Use the Segment Addition Postulate (part + part = whole) to find the measure of x.

Solution

To solve this problem, we will use the Segment Addition Postulate, which states that the sum of the lengths of the smaller segments will equal the total length of the larger segment.

Given:

  1. ST=13ST = 13
  2. TU=6TU = 6
  3. UV=2x18UV = 2x - 18
  4. The total length SV=4x29SV = 4x - 29

According to the Segment Addition Postulate: ST+TU+UV=SVST + TU + UV = SV

Substitute the given values: 13+6+(2x18)=4x2913 + 6 + (2x - 18) = 4x - 29

Let's simplify and solve for xx:

  1. Combine like terms on the left side: 19+2x18=4x2919 + 2x - 18 = 4x - 29

  2. Simplify further: 1+2x=4x291 + 2x = 4x - 29

  3. Subtract 2x2x from both sides: 1=2x291 = 2x - 29

  4. Add 29 to both sides: 30=2x30 = 2x

  5. Divide by 2: x=15x = 15

So, the measure of xx is 15.

Would you like me to go into further detail or do you have any specific questions?

Related Questions:

  1. What is the length of segment UVUV when x=15x = 15?
  2. What is the length of segment SVSV using the value of xx?
  3. Can the Segment Addition Postulate be applied to other geometric figures?
  4. How would the equation change if segment TUTU had a different length?
  5. What other geometric properties rely on the Segment Addition Postulate?

Tip:

When solving for variables, always check your solution by substituting the value back into the original equations to verify accuracy.

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Math Problem Analysis

Mathematical Concepts

Algebra
Geometry
Segment Addition Postulate

Formulas

ST + TU + UV = SV

Theorems

Segment Addition Postulate

Suitable Grade Level

Grades 7-9