Math Problem Statement
A spy satellite is in circular orbit around Earth. It makes one revolution in 7.50 h. Mass of Earth is 5.974 × 1024 kg, radius of Earth is 6371 km and Gravitational constant G is = 6.674 × 10−11 N·m2/kg2.
How high above Earth’s surface is the satellite?
Solution
To determine the height of the satellite above Earth's surface, we need to use the following concepts and equations from orbital mechanics:
-
Gravitational force is providing the necessary centripetal force for the satellite to stay in orbit.
The gravitational force equation is: where:
- is the gravitational constant,
- is the mass of the Earth,
- is the mass of the satellite,
- is the distance from the center of the Earth to the satellite.
-
Centripetal force required to maintain the satellite in a circular orbit is given by: where:
- is the orbital velocity of the satellite,
- is the distance from the center of the Earth to the satellite.
-
From these two expressions, we equate the gravitational force to the centripetal force:
Simplifying this:
-
The satellite’s velocity is also related to the orbital period (the time it takes for one complete revolution) by:
-
Substituting this expression for into the previous equation:
-
Rearranging for , we get:
-
Now, we can solve for (the orbital radius from the center of the Earth) and then subtract the Earth's radius to get the satellite's height above the surface.
Let's calculate this step-by-step.The height of the satellite above Earth's surface is approximately .
Would you like more details on the calculation, or have any further questions?
Here are 5 related questions you might explore:
- How does changing the satellite's orbital period affect its altitude?
- What is the satellite's orbital velocity at this altitude?
- How would the height change if the satellite orbited a different planet?
- What is the gravitational force acting on the satellite at this altitude?
- How does Earth's mass influence satellite orbits?
Tip: Orbital period and altitude are linked via Kepler's third law, which states that a satellite farther from Earth takes longer to complete an orbit.
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Math Problem Analysis
Mathematical Concepts
Orbital Mechanics
Gravitational Force
Centripetal Force
Kepler's Third Law
Formulas
Gravitational force: F = G * M * m / r^2
Centripetal force: F = m * v^2 / r
Orbital velocity: v = 2 * π * r / T
Orbital radius: r^3 = G * M * T^2 / 4 * π^2
Theorems
Kepler's Third Law
Suitable Grade Level
Undergraduate
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