Math Problem Statement
A satellite moves in a circular orbit around the Earth at a speed of 6.4 km/s. Determine the satellite’s altitude above the surface of the Earth. Assume the Earth is a homogeneous sphere of radius 6370 km and mass 5.98 × 1024 kg. The value of the universal gravitational constant is 6.67259 × 10−11 N · m2/kg2 Answer in units of km.
Solution
To determine the satellite's altitude, we can use the principles of gravitational force and centripetal force, which are in balance for a satellite in a stable circular orbit.
The gravitational force acting on the satellite is given by:
Where:
- is the universal gravitational constant, ,
- is the mass of the Earth, ,
- is the mass of the satellite (it cancels out in the final equation),
- is the distance from the center of the Earth to the satellite.
The centripetal force required to keep the satellite in orbit is given by:
Where:
- is the orbital speed of the satellite.
Since the gravitational force provides the necessary centripetal force, we set the two forces equal to each other:
The mass of the satellite cancels out:
Multiplying both sides by , we get:
Solving for :
Now, let's plug in the values:
- ,
- ,
- .
Once we find , we can subtract the Earth's radius to find the altitude:
Where .
Let me calculate this for you.The satellite's altitude above the surface of the Earth is approximately .
Would you like more details or have any questions?
Here are five related questions:
- How does the mass of the satellite affect its orbital altitude?
- What would happen if the satellite's speed was higher than ?
- How does the altitude change if the Earth's mass were different?
- What other forces (e.g., atmospheric drag) can affect a satellite's orbit at low altitudes?
- How can this calculation change for elliptical orbits?
Tip: The velocity of a satellite in orbit is directly dependent on its altitude—the higher the altitude, the lower the orbital speed needed for a stable orbit.
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Math Problem Analysis
Mathematical Concepts
Gravitational Force
Centripetal Force
Orbital Mechanics
Formulas
F_g = (G * M * m) / r^2
F_c = (m * v^2) / r
Gravitational force equals centripetal force: G * M / r^2 = v^2 / r
r = G * M / v^2
Altitude = r - Earth's radius
Theorems
Newton's Law of Universal Gravitation
Suitable Grade Level
Grades 11-12