Math Problem Statement

For a satellite circuit the carrier-to-noise ratios are uplink 23 dB, downlink 20 dB, intermodulation 24 dB. Calculate the overall carrier- to-noise ratio in decibels.

Solution

The overall carrier-to-noise ratio (C/N)overall(C/N)_{\text{overall}} in a satellite circuit can be calculated using the reciprocal of the sum of the reciprocals of the individual C/NC/N values for each link in the system. This relationship is derived from the nature of signal-to-noise ratios (SNR) in cascaded systems.

For the uplink, downlink, and intermodulation components, the overall C/NC/N is given by:

1(C/N)overall=1(C/N)uplink+1(C/N)downlink+1(C/N)intermodulation\frac{1}{(C/N)_{\text{overall}}} = \frac{1}{(C/N)_{\text{uplink}}} + \frac{1}{(C/N)_{\text{downlink}}} + \frac{1}{(C/N)_{\text{intermodulation}}}

We are provided with the following values in dB:

  • (C/N)uplink=23dB(C/N)_{\text{uplink}} = 23 \, \text{dB}
  • (C/N)downlink=20dB(C/N)_{\text{downlink}} = 20 \, \text{dB}
  • (C/N)intermodulation=24dB(C/N)_{\text{intermodulation}} = 24 \, \text{dB}

Step 1: Convert dB values to linear scale

The C/NC/N ratio in linear form is given by:

C/Nlinear=10C/NdB/10C/N_{\text{linear}} = 10^{C/N_{\text{dB}}/10}

Applying this to each value:

  • (C/N)uplink=1023/10=199.53(C/N)_{\text{uplink}} = 10^{23/10} = 199.53
  • (C/N)downlink=1020/10=100.00(C/N)_{\text{downlink}} = 10^{20/10} = 100.00
  • (C/N)intermodulation=1024/10=251.19(C/N)_{\text{intermodulation}} = 10^{24/10} = 251.19

Step 2: Use the reciprocal formula

Now, calculate the reciprocal sum of these values:

1(C/N)overall=1199.53+1100.00+1251.19\frac{1}{(C/N)_{\text{overall}}} = \frac{1}{199.53} + \frac{1}{100.00} + \frac{1}{251.19}

1(C/N)overall=0.00501+0.01+0.00398=0.01899\frac{1}{(C/N)_{\text{overall}}} = 0.00501 + 0.01 + 0.00398 = 0.01899

Step 3: Invert to find the overall C/NC/N in linear scale

(C/N)overall=10.01899=52.64(C/N)_{\text{overall}} = \frac{1}{0.01899} = 52.64

Step 4: Convert back to decibels

(C/N)overall=10log10(52.64)17.21dB(C/N)_{\text{overall}} = 10 \cdot \log_{10}(52.64) \approx 17.21 \, \text{dB}

Final Answer:

The overall carrier-to-noise ratio is approximately 17.21 dB.

Would you like more details or have any questions?

Here are five related questions:

  1. How does intermodulation noise affect satellite communication systems?
  2. Why are carrier-to-noise ratios often expressed in decibels?
  3. How would the overall C/N ratio change if the uplink ratio decreased?
  4. What are other common sources of noise in satellite communication systems?
  5. How is C/NC/N different from Eb/N0E_b/N_0 in communication systems?

Tip: Always convert dB values to linear form when working with ratios like C/NC/N before applying mathematical operations.

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Math Problem Analysis

Mathematical Concepts

Signal-to-Noise Ratios
Logarithmic Calculations
Decibel Conversions

Formulas

Overall Carrier-to-Noise Ratio: 1/(C/N)_{overall} = 1/(C/N)_{uplink} + 1/(C/N)_{downlink} + 1/(C/N)_{intermodulation}
C/N linear conversion: C/N_{linear} = 10^{(C/N_{dB}) / 10}
Decibel conversion: C/N_{dB} = 10 * log10(C/N_{linear})

Theorems

Properties of Logarithms
Cascaded System SNR Calculation

Suitable Grade Level

Undergraduate Level