The city of Raleigh has 9600 registered voters. There are two candidates for city council in an upcoming election: Brown and Feliz. The day before the election, a telephone poll of 450 randomly selected registered voters was conducted. 197 said they'd vote for Brown, 230 said they'd vote for Feliz, and 23 were undecided.

Give the sample statistic for the proportion of voters surveyed who said they'd vote for Brown. Note: The proportion should be a fraction or decimal, not a percent.

To find the sample statistic for the proportion of voters surveyed who said they'd vote for Brown, we divide the number of voters who said they'd vote for Brown by the total number of voters surveyed.

The number of voters who said they'd vote for Brown is 197, and the total number of voters surveyed is 450.

So, the proportion is:

\[
\text{Proportion} = \frac{197}{450} \approx 0.4378
\]

Thus, the sample statistic for the proportion of voters surveyed who said they'd vote for Brown is approximately \( 0.4378 \) (or \( \frac{197}{450} \) in fractional form).

Would you like more details or have any questions?

Here are five related questions to expand your understanding:
1. How would you find the proportion of voters who said they'd vote for Feliz?
2. What is the proportion of undecided voters in the survey?
3. How can we estimate the total number of voters who might vote for Brown in the entire population of 9600 registered voters?
4. What would the proportion be if more voters were undecided?
5. How could we calculate the margin of error for this poll?

**Tip:** Always check that the total number of surveyed voters matches the sum of all choices (Brown, Feliz, and undecided) to ensure data consistency.

Learn how to calculate the sample proportion of voters who said they'd vote for Brown in a telephone poll of 450 registered voters in Raleigh. This problem covers key statistical concepts, including proportions and sampling methods, suitable for students in Grades 9-12.

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