Math Problem Statement
Perform one step of row reduction, in order to calculate the values for x and y by back substitution. Then calculate the values for x and y. Also calculate the determinant of the original matrix. ( Note: since the determinant is unchanged by type 3 row operations, it will be easier to calculate the determinant of the row reduced matrix.)
\left[\begin{array}{cc} 7 &27\cr 9 &-11 \end{array}\right] \left\lbrack \begin{array}{c} x \ y \end{array} \right\rbrack
\left[\begin{array}{c} 5\cr 2 \end{array}\right]
\left.\vphantom{\begin{array}{c}!\strut\!\strut\!\strut\\end{array}}\right[ 7 27 \left.\vphantom{\begin{array}{c}!\strut\!\strut\!\strut\\end{array}}\right] 0 \left.\vphantom{\begin{array}{c}!\strut\!\strut\!\strut\\end{array}}\right[ x \left.\vphantom{\begin{array}{c}!\strut\!\strut\!\strut\\end{array}}\right] y
\left.\vphantom{\begin{array}{c}!\strut\!\strut\!\strut\\end{array}}\right[ 5 \left.\vphantom{\begin{array}{c}!\strut\!\strut\!\strut\\end{array}}\right]
x =
y =
\mbox{det} =
Solution
Given System of Equations:
We are given the matrix equation:
[ \left[\begin{array}{cc} 7 & 27 \ 9 & -11 \end{array}\right] \left[\begin{array}{c} x \ y \end{array}\right] = \left[\begin{array}{c} 5 \ 2 \end{array}\right] ]
Step 1: Row Reduction
To solve for and , we will perform row reduction (Gaussian elimination). The goal is to transform the system into an upper triangular form so that back substitution can be used to solve for and .
The system is:
To eliminate from the second equation, we can perform the following row operation:
Step-by-Step Row Operation:
-
The first equation remains the same:
-
Subtract times the first row from the second row:
Simplify:
This simplifies to:
Multiply through by 7 to simplify:
Solve for :
Step 2: Back Substitution
Now that we have , we substitute this value into the first equation to solve for :
Simplify:
Multiply both sides by 320 to eliminate the fraction:
Solve for :
Thus, the solution is:
Step 3: Calculate the Determinant
The determinant of the original matrix is:
Final Answer:
Would you like further details or have any questions?
Here are some related questions:
- How does Gaussian elimination differ from row reduction?
- Can the determinant of a matrix ever be zero?
- How are type 3 row operations used in matrix reduction?
- What is the significance of the determinant in a system of equations?
- How do row operations affect the determinant of a matrix?
Tip: When the determinant of a matrix is zero, the system of equations has either no solution or infinitely many solutions.
Ask a new question for Free
By Image
Drop file here or Click Here to upload
Math Problem Analysis
Mathematical Concepts
Linear Algebra
Row Reduction
Gaussian Elimination
Determinants
Back Substitution
Formulas
Row Reduction: R2 -> R2 - (9/7)R1
Back Substitution
Determinant: det(A) = ad - bc
Theorems
Gaussian Elimination
Properties of Determinants
Suitable Grade Level
College level (Linear Algebra)