Math Problem Statement

Say that ζ = e^(iθ) = cos(θ) + i sin(θ). Show that the map ρ_ζ : ℝ² → ℝ² defined by ρ_ζ(x) = ζ · x is the rotation of the complex plane by the angle θ.

Solution

The problem you provided asks to show that the map ρζ:R2R2\rho_{\zeta} : \mathbb{R}^2 \to \mathbb{R}^2, defined by ρζ(x)=ζx\rho_{\zeta}(x) = \zeta \cdot x, represents the rotation of the complex plane by the angle θ\theta, where ζ=eiθ=cos(θ)+isin(θ)\zeta = e^{i\theta} = \cos(\theta) + i \sin(\theta).

Solution Outline:

  1. Interpretation of the map ρζ\rho_{\zeta}:

    • The complex number ζ=eiθ\zeta = e^{i\theta} represents a point on the unit circle in the complex plane. Multiplication by ζ\zeta rotates any complex number by the angle θ\theta.
    • Given xR2x \in \mathbb{R}^2, think of xx as a vector in the complex plane, identified as x1+ix2x_1 + ix_2, where x=(x1,x2)x = (x_1, x_2).
  2. Multiplying by ζ\zeta:

    • To rotate a vector x=x1+ix2x = x_1 + ix_2 by an angle θ\theta, we multiply it by ζ=cos(θ)+isin(θ)\zeta = \cos(\theta) + i \sin(\theta): ζx=(cos(θ)+isin(θ))(x1+ix2)\zeta \cdot x = (\cos(\theta) + i \sin(\theta))(x_1 + ix_2) Expanding this: ζx=cos(θ)(x1+ix2)+isin(θ)(x1+ix2)\zeta \cdot x = \cos(\theta)(x_1 + ix_2) + i \sin(\theta)(x_1 + ix_2) Simplifying this expression yields: =cos(θ)x1sin(θ)x2+i(sin(θ)x1+cos(θ)x2)= \cos(\theta) x_1 - \sin(\theta) x_2 + i(\sin(\theta) x_1 + \cos(\theta) x_2) This can be separated into its real and imaginary parts: =(cos(θ)x1sin(θ)x2)+i(sin(θ)x1+cos(θ)x2)= (\cos(\theta) x_1 - \sin(\theta) x_2) + i(\sin(\theta) x_1 + \cos(\theta) x_2) Therefore, after rotation by θ\theta, the new coordinates are: (cos(θ)x1sin(θ)x2,sin(θ)x1+cos(θ)x2)(\cos(\theta) x_1 - \sin(\theta) x_2, \sin(\theta) x_1 + \cos(\theta) x_2) This is the standard form of a 2D rotation matrix applied to (x1,x2)(x_1, x_2): \cos(\theta) & -\sin(\theta) \\ \sin(\theta) & \cos(\theta) \end{pmatrix} \begin{pmatrix} x_1 \\ x_2 \end{pmatrix}$$ which confirms that multiplication by $$\zeta = e^{i\theta}$$ rotates the vector by $$\theta$$.

Conclusion:

Thus, we have shown that the map ρζ(x)=ζx\rho_{\zeta}(x) = \zeta \cdot x is indeed the rotation of the complex plane by the angle θ\theta.

Would you like more details on any part of this solution?


Here are five related questions you might explore next:

  1. How does the rotation matrix change if the angle θ\theta is negative?
  2. What is the geometric interpretation of multiplying a complex number by eiθe^{-i\theta}?
  3. Can we extend this concept of rotation to 3D space? If so, how?
  4. How would you prove the same result using polar coordinates instead of Cartesian?
  5. What happens to a complex number when multiplied by ζ=eiπ\zeta = e^{i\pi}?

Tip: Complex number multiplication often leads to rotations and scalings in the plane, a key concept in both algebra and geometry.

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Math Problem Analysis

Mathematical Concepts

Complex Numbers
Rotation in the Complex Plane
Linear Algebra

Formulas

ζ = e^(iθ) = cos(θ) + i sin(θ)
Rotation matrix: [[cos(θ), -sin(θ)], [sin(θ), cos(θ)]]

Theorems

Euler's Formula: e^(iθ) = cos(θ) + i sin(θ)
Rotation of the complex plane by multiplication of complex numbers

Suitable Grade Level

Undergraduate level (Advanced Linear Algebra, Complex Analysis)