Math Problem Statement

A rocket is launched from a tower. The height of the rocket, y in feet, is related to the time after launch, x in seconds, by the given equation. Using this equation, find the time that the rocket will hit the ground, to the nearest 100th of second. y, equals, minus, 16, x, squared, plus, 231, x, plus, 71 y=−16x 2 +231x+71

Solution

To find the time when the rocket will hit the ground, we need to determine when the height yy equals zero. This corresponds to the point when the rocket reaches the ground.

The equation given for the height yy is:

y=16x2+231x+71y = -16x^2 + 231x + 71

We set y=0y = 0 to find the time xx when the rocket hits the ground:

0=16x2+231x+710 = -16x^2 + 231x + 71

This is a quadratic equation in the form ax2+bx+c=0ax^2 + bx + c = 0, where:

  • a=16a = -16
  • b=231b = 231
  • c=71c = 71

We will solve for xx using the quadratic formula, which is:

x=b±b24ac2ax = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}

Step 1: Calculate the discriminant

The discriminant is the part under the square root, b24acb^2 - 4ac:

b24ac=23124(16)(71)b^2 - 4ac = 231^2 - 4(-16)(71)

b24ac=53361+4544b^2 - 4ac = 53361 + 4544

b24ac=57905b^2 - 4ac = 57905

Step 2: Apply the quadratic formula

Now, we can compute the values for xx:

x=231±579052(16)x = \frac{-231 \pm \sqrt{57905}}{2(-16)}

The square root of 5790557905 is approximately 240.58240.58. So,

x=231±240.5832x = \frac{-231 \pm 240.58}{-32}

Step 3: Calculate the two possible values for xx

  1. Using the positive root:

x1=231+240.5832=9.58320.30x_1 = \frac{-231 + 240.58}{-32} = \frac{9.58}{-32} \approx -0.30

  1. Using the negative root:

x2=231240.5832=471.583214.73x_2 = \frac{-231 - 240.58}{-32} = \frac{-471.58}{-32} \approx 14.73

Since the negative time doesn't make sense in this context, we discard x1x_1 and keep the positive value, which is:

x14.73secondsx \approx 14.73 \, \text{seconds}

Final Answer:

The rocket will hit the ground after approximately 14.73 seconds.

Would you like more details on the solution, or have any questions about this process?

Related Questions:

  1. How would the solution change if the rocket's initial height were different?
  2. What would happen if the rocket's initial velocity were lower or higher?
  3. How do you solve quadratic equations when the discriminant is negative?
  4. How can we find the maximum height of the rocket from the equation?
  5. What happens if the coefficient of x2x^2 is positive instead of negative in the equation?

Tip:

In real-world applications, quadratic equations like this one are often used to model projectile motion, but always make sure to interpret your results in the context of the problem!

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Math Problem Analysis

Mathematical Concepts

Algebra
Quadratic Equations
Projectile Motion

Formulas

Quadratic equation formula ax^2 + bx + c = 0
Quadratic formula x = (-b ± √(b^2 - 4ac)) / 2a

Theorems

Quadratic formula

Suitable Grade Level

Grades 9-11