Alanq and Harrison played 60 games of rock-paper-scissors. Alana won 45% of the games and Harrison won 20% of the games. How much games did they draw?

To solve this problem, let's break it down step by step:

1. **Total number of games played**: 60
2. **Percentage of games Alana won**: 45%
3. **Percentage of games Harrison won**: 20%

Now, we calculate the number of games won by Alana and Harrison:

- **Games won by Alana**:
  \[
  45\% \text{ of } 60 = 0.45 \times 60 = 27 \text{ games}
  \]

- **Games won by Harrison**:
  \[
  20\% \text{ of } 60 = 0.20 \times 60 = 12 \text{ games}
  \]

Now, the total number of games won by both Alana and Harrison is:
\[
27 + 12 = 39 \text{ games}
\]

Finally, to find the number of games they drew, subtract the total number of wins (39) from the total number of games (60):
\[
60 - 39 = 21 \text{ draws}
\]

Thus, they drew **21 games**.

Would you like further details or have any questions?

Here are 5 related questions for further exploration:
1. What percentage of the games ended in a draw?
2. If they played 80 games instead, how many draws would there be with the same win rates?
3. What if Harrison's win percentage increased by 10%? How would this affect the number of draws?
4. How many games would Alana need to win to achieve a 50% win rate?
5. If a third player entered the game and won 15% of the matches, how would this change the outcome?

**Tip**: Always check if the sum of win percentages leaves enough room for draws.

Learn how to solve a rock-paper-scissors problem where Alana wins 45%, Harrison wins 20%, and the remaining games are draws. Find out how to calculate the number of draws in 60 games using percentage calculations. Suitable for students in Grades 5-7.

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