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The problem asks: *Harrison and Alwine have 72 cards to sign. Harrison signs \(\frac{1}{3}\) of the cards, while Alwine signs \(\frac{3}{8}\) of the cards. How many cards are left to be signed?*

Let's break it down step-by-step:

1. **Harrison's cards**: He signs \(\frac{1}{3}\) of 72 cards, so:
   \[
   \text{Harrison's cards} = \frac{1}{3} \times 72 = 24 \text{ cards}
   \]

2. **Alwine's cards**: She signs \(\frac{3}{8}\) of 72 cards, so:
   \[
   \text{Alwine's cards} = \frac{3}{8} \times 72 = 27 \text{ cards}
   \]

3. **Total signed cards**: 
   \[
   \text{Total signed cards} = 24 + 27 = 51 \text{ cards}
   \]

4. **Cards left to be signed**: 
   \[
   \text{Remaining cards} = 72 - 51 = 21 \text{ cards}
   \]

Thus, there are **21 cards left to be signed**.

Would you like more details or have any other questions?

Here are 5 related questions:
1. What if Harrison signed \(\frac{1}{4}\) of the cards instead?
2. How many cards would be left if Alwine signed \(\frac{1}{2}\) of the total?
3. How many cards would remain if 10 more cards were added to the initial total?
4. What if both signed the same fraction of cards, say \(\frac{1}{5}\)?
5. How many cards would remain if Harrison signed \(\frac{2}{3}\) of the cards?

**Tip**: Whenever solving problems involving fractions, it's helpful to first calculate individual contributions before summing them to find the remaining portion.

Harrison and Alwine have 72 cards to sign. Harrison signs 1/3 of the cards, while Alwine signs 3/8 of the cards. How many cards are left to be signed?

Solve the problem where Harrison and Alwine have 72 cards to sign. Harrison signs 1/3 of the cards, while Alwine signs 3/8 of them. Learn how to calculate the number of cards left to be signed using basic fraction operations. Suitable for Grades 5-7.

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