This is a right triangle problem, where we need to solve for the side $x$ using trigonometric functions. Here’s a breakdown of the steps:

1. Given:

   • Angle $\angle ECD = 62^\circ$ (angle adjacent to side CD).
   • $CD = 15$ (the side adjacent to the angle).
   • $x = ED$ (the opposite side).

2. Trigonometric Function: Since we know the angle and the adjacent side, and we need to find the opposite side, we use the tangent function: $\tan(\theta) = \frac{\text{opposite}}{\text{adjacent}}$ In this case: $\tan(62^\circ) = \frac{x}{15}$

3. Solving for $x$: $x = 15 \times \tan(62^\circ)$

I will calculate this now.The length of side $x$ (opposite to the given angle) is approximately 28.2 when rounded to the nearest tenth.

Would you like more details or further clarification on any steps?

Here are 5 related questions for further practice:

1. How would you calculate the hypotenuse of this triangle?
2. What if the angle was $45^\circ$? How would that affect $x$?
3. Can you use the sine or cosine functions to solve for $x$?
4. How can you verify the answer using the Pythagorean theorem?
5. What is the measure of the third angle in this triangle?

Tip: Always keep track of which trigonometric function to use based on the sides involved (opposite, adjacent, hypotenuse).