To find the resultant of the forces at Point A, we need to analyze the direction and magnitude of each force, then apply vector addition.

From the image, two forces are acting at Point A:

• $F1 = 10 \, \text{kips}$ directed at a downward angle from the vertical axis.
• $F2 = 15 \, \text{kips}$ directed horizontally.

The angle for $F1$ can be determined using the triangle shown around point A, which has sides of 1 unit and 3 units. The angle $\theta$ from the horizontal can be calculated as: $\tan^{-1}\left(\frac{1}{3}\right)$

The components of $F1$ are:

• Vertical: $F1_y = 10 \cos(\theta)$
• Horizontal: $F1_x = 10 \sin(\theta)$

The components of $F2$ are purely horizontal:

• $F2_x = 15 \, \text{kips}$

The net force components are:

• Net horizontal: $F_{\text{net, x}} = F1_x + F2_x$
• Net vertical: $F_{\text{net, y}} = F1_y$ (Since $F2$ does not have a vertical component)

The magnitude of the resultant force is: $R = \sqrt{F_{\text{net, x}}^2 + F_{\text{net, y}}^2}$

The angle $\phi$ of the resultant with respect to the horizontal is: $\phi = \tan^{-1}\left(\frac{F_{\text{net, y}}}{F_{\text{net, x}}}\right)$

Let's perform these calculations.The resultant of the forces at Point A is approximately $20.49$ kips, directed at an angle of $27.58^\circ$ from the horizontal.

Would you like to explore more details or have any other questions on this topic?

Here are some related questions you might consider:

1. How would the resultant force change if the angle of $F1$ was steeper or shallower?
2. What happens to the resultant force if $F1$ and $F2$ are in opposite directions?
3. How does changing the magnitudes of $F1$ or $F2$ affect the resultant?
4. Can you calculate the work done if these forces moved an object along the horizontal?
5. What additional forces would balance these two forces at Point A, making the resultant zero?

Tip: When working with forces in different directions, always break them down into their horizontal and vertical components to simplify calculations.