Math Problem Statement

Jika F1 = 15√2 N; F2 = 10 N; F3 = 20 N, maka besar resultan dan arahnya terhadap sumbu x positif adalah …

Solution

The problem is to find the resultant force (RR) and its direction with respect to the positive xx-axis, given three forces:

  1. F1=152NF_1 = 15\sqrt{2} \, \text{N}, directed at a 45° angle from the positive xx-axis.
  2. F2=10NF_2 = 10 \, \text{N}, directed along the negative xx-axis.
  3. F3=20NF_3 = 20 \, \text{N}, directed along the negative yy-axis.

Solution:

Step 1: Resolve F1F_1 into xx- and yy-components.

Given that F1=152NF_1 = 15\sqrt{2} \, \text{N} is at a 45° angle:

  • F1x=F1cos(45)=15222=15NF_{1x} = F_1 \cos(45^\circ) = 15\sqrt{2} \cdot \frac{\sqrt{2}}{2} = 15 \, \text{N}
  • F1y=F1sin(45)=15222=15NF_{1y} = F_1 \sin(45^\circ) = 15\sqrt{2} \cdot \frac{\sqrt{2}}{2} = 15 \, \text{N}

Step 2: Identify the xx- and yy-components of F2F_2 and F3F_3.

  • F2F_2 acts along the negative xx-axis, so:
    • F2x=10NF_{2x} = -10 \, \text{N}
    • F2y=0NF_{2y} = 0 \, \text{N}
  • F3F_3 acts along the negative yy-axis, so:
    • F3x=0NF_{3x} = 0 \, \text{N}
    • F3y=20NF_{3y} = -20 \, \text{N}

Step 3: Calculate the total xx- and yy-components.

Rx=F1x+F2x+F3x=1510+0=5NR_x = F_{1x} + F_{2x} + F_{3x} = 15 - 10 + 0 = 5 \, \text{N} Ry=F1y+F2y+F3y=15+020=5NR_y = F_{1y} + F_{2y} + F_{3y} = 15 + 0 - 20 = -5 \, \text{N}

Step 4: Calculate the magnitude of the resultant force RR.

R=Rx2+Ry2=52+(5)2=25+25=50=52NR = \sqrt{R_x^2 + R_y^2} = \sqrt{5^2 + (-5)^2} = \sqrt{25 + 25} = \sqrt{50} = 5\sqrt{2} \, \text{N}

Step 5: Determine the angle θ\theta of RR with respect to the positive xx-axis.

θ=tan1(RyRx)=tan1(55)=tan1(1)=45\theta = \tan^{-1}\left(\frac{R_y}{R_x}\right) = \tan^{-1}\left(\frac{-5}{5}\right) = \tan^{-1}(-1) = -45^\circ Since RyR_y is negative and RxR_x is positive, the resultant vector RR is directed 45° below the positive xx-axis.

Final Answer:

  • The magnitude of the resultant force RR is 52N5\sqrt{2} \, \text{N}.
  • The direction of RR is 45° below the positive xx-axis (or 45-45^\circ with respect to the positive xx-axis).

Would you like a breakdown of any step or additional clarification?


  1. How can we verify the resultant direction using vector addition?
  2. What would change if the angle of F1F_1 were different?
  3. How does knowing the direction help in practical applications?
  4. What is the impact of each force component on the resultant?
  5. How could this problem change if we used different coordinate systems?

Tip: Always resolve forces into components to simplify calculations in vector problems.

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Math Problem Analysis

Mathematical Concepts

Vector Addition
Trigonometry
Vector Components

Formulas

R = √(Rx^2 + Ry^2)
Rx = F1x + F2x + F3x
Ry = F1y + F2y + F3y
F1x = F1 * cos(θ)
F1y = F1 * sin(θ)
θ = tan⁻¹(Ry / Rx)

Theorems

Pythagorean Theorem
Trigonometric Identities

Suitable Grade Level

Grades 10-12