Math Problem Statement

Решить задачу анализа для Релейно-Контактная Схемы

Решить задачу анализа для Релейно-Контактная Схемы

Solution

The image contains a relay-contact scheme. I will analyze the circuit step by step to determine the logic function ff based on the inputs xx, yy, and zz.

Step-by-Step Analysis

  1. Input Components:

    • Inputs xx, yy, and zz control the circuit.
  2. Logic Gates:

    • The circuit contains basic logical components: AND (&\&), OR (++), and equality (==) gates.
    • A logical negation or complement is applied to one input.
  3. Path Analysis:

    • Trace the paths and interactions of x,y,zx, y, z, through each gate step by step.

Let’s derive the function ff:

  • xx: Appears as input to an AND gate. After analyzing the relay-contact scheme in the image, here's a detailed breakdown of the logical structure and the resulting function ff:

Key Observations

  1. Inputs:

    • Inputs are xx, yy, and zz.
  2. Logic Gates:

    • Two AND gates (&\&).
    • One OR gate.
    • One equality comparison gate (==).
    • Input negation (denoted by a small circle) is applied to certain signals.
  3. Connections:

    • yy and zz are fed into the equality gate (==), which outputs 11 if y=zy = z.
    • xx directly interacts with these outputs through additional AND gates.
    • The outputs of the gates are combined logically to produce ff.

Step-by-Step Logical Expression Derivation

Step 1: Equality Gate (y=zy = z):

  • The equality gate outputs 11 if y=zy = z, so its output can be written as: Equality Output: E=(yz)+(yz).\text{Equality Output: } E = (y \cdot z') + (y' \cdot z).

Step 2: First AND Gate:

  • One AND gate takes the inputs xx and EE: A1=xE.A_1 = x \cdot E. Substituting EE: A1=x[(yz)+(yz)].A_1 = x \cdot [(y \cdot z') + (y' \cdot z)].

Step 3: Second AND Gate:

  • Another AND gate directly combines xx with yy: A2=xy.A_2 = x \cdot y.

Step 4: OR Gate:

  • The final output ff is the OR of the two AND gate outputs: f=A1+A2.f = A_1 + A_2. Substituting A1A_1 and A2A_2: f=[x((yz)+(yz))]+(xy).f = [x \cdot ((y \cdot z') + (y' \cdot z))] + (x \cdot y).

Step 5: Simplify ff:

  • Distribute and simplify: f=(xyz)+(xyz)+(xy).f = (x \cdot y \cdot z') + (x \cdot y' \cdot z) + (x \cdot y).

Final Logic Function:

The resulting logic function is: f=xy+xyz+xyz.f = x \cdot y + x \cdot y' \cdot z + x \cdot y \cdot z'.

This is the simplified expression for the relay-contact circuit.


Do you have questions or need further details?

Related Questions:

  1. What does the equality gate specifically do in such circuits?
  2. Can the logic function ff be represented using Karnaugh maps?
  3. How would the circuit behave for specific input combinations of x,y,zx, y, z?
  4. Can we design an equivalent digital circuit for this relay-contact scheme?
  5. What practical applications exist for such relay circuits?

Tip: To validate logic circuits, use truth tables or simulation software to check your derived expression.

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Math Problem Analysis

Mathematical Concepts

Logic Circuits
Boolean Algebra
Relay-Contact Analysis

Formulas

Equality Gate Output: E = (y · z') + (y' · z)
Logic Function: f = (x · y) + (x · y' · z) + (x · y · z')

Theorems

Boolean Algebra Laws
Simplification of Logical Expressions

Suitable Grade Level

Undergraduate Electrical Engineering or Computer Science