Math Problem Statement

A regression analysis from a sample of

1515

produced the results shown below. Complete parts a through c. Use a

9090​%

confidence level where needed.

Summation from nothing to nothing left parenthesis x Subscript i Baseline minus x overbar right parenthesis left parenthesis y Subscript i Baseline minus y overbar right parenthesis∑xi−xyi−y

equals=

153.6153.6

Summation from nothing to nothing left parenthesis y Subscript i Baseline minus ModifyingAbove y with caret right parenthesis squared∑yi−y2

equals=

39.53239.532

Summation from nothing to nothing left parenthesis x Subscript i Baseline minus x overbar right parenthesis squared∑xi−x2

equals=

176.4176.4

x overbarx

equals=

18.918.9

Summation from nothing to nothing left parenthesis y Subscript i Baseline minus y overbar right parenthesis squared∑yi−y2

equals=

182.6182.6

y overbary

equals=

50.550.5

Question content area bottom

Part 1

a. Produce the regression line.

ModifyingAbove y with caretyequals=enter your response hereplus+enter your response herex

​(Round to four decimal places as​ needed.)

Solution

To produce the regression line, we need to calculate the slope (bb) and the intercept (aa) for the regression equation:

y^=a+bx\hat{y} = a + b x

Step 1: Calculate the Slope (bb)

The formula for the slope bb is: b=(xixˉ)(yiyˉ)(xixˉ)2b = \frac{\sum (x_i - \bar{x})(y_i - \bar{y})}{\sum (x_i - \bar{x})^2}

Using the values given: (xixˉ)(yiyˉ)=153.6\sum (x_i - \bar{x})(y_i - \bar{y}) = 153.6 (xixˉ)2=176.4\sum (x_i - \bar{x})^2 = 176.4

Substitute these values into the formula: b=153.6176.4b = \frac{153.6}{176.4}

Calculating: b0.8708b \approx 0.8708

Step 2: Calculate the Intercept (aa)

The formula for the intercept aa is: a=yˉbxˉa = \bar{y} - b \cdot \bar{x}

Using: yˉ=50.5,xˉ=18.9\bar{y} = 50.5, \quad \bar{x} = 18.9

Substitute bb and these values into the formula: a=50.5(0.8708×18.9)a = 50.5 - (0.8708 \times 18.9)

Calculating: a33.0379a \approx 33.0379

Final Regression Line

Now that we have both aa and bb, we can write the regression line: y^=33.0379+0.8708x\hat{y} = 33.0379 + 0.8708x

Final Answer

y^=33.0379+0.8708x\hat{y} = 33.0379 + 0.8708x

Would you like further details on the calculations, or do you have any other questions?


Here are five related questions:

  1. How is the slope of a regression line interpreted in a real-world context?
  2. What does the intercept represent in a regression analysis?
  3. How does the confidence level affect the interpretation of the regression line?
  4. What is the purpose of calculating the sum of squares in regression?
  5. How would you interpret the strength of the relationship between xx and yy here?

Tip: Always check the residuals after creating a regression line to assess the fit of the model.

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Math Problem Analysis

Mathematical Concepts

Regression Analysis
Linear Regression
Statistics

Formulas

Regression Line Formula: \hat{y} = a + b x
Slope Formula: b = (Σ(x_i - x̄)(y_i - ȳ)) / Σ(x_i - x̄)^2
Intercept Formula: a = ȳ - b * x̄

Theorems

Least Squares Regression
Properties of the Regression Line

Suitable Grade Level

Grades 11-12