Math Problem Statement

Write a recursive formula for 4+(n-1)*6

Solution

The explicit formula given is:

an=4+(n1)6a_n = 4 + (n-1) \cdot 6

To write a recursive formula, we express ana_n in terms of the previous term an1a_{n-1}. Here's how we do it:

Step 1: General Pattern

Each term in the sequence increases by 66 compared to the previous term. Thus: an=an1+6a_n = a_{n-1} + 6

Step 2: Specify the Base Case

The first term of the sequence is: a1=4a_1 = 4

Final Recursive Formula:

an=an1+6,for n2a_n = a_{n-1} + 6, \quad \text{for } n \geq 2 a1=4a_1 = 4

Would you like to see this formula applied to specific values, or do you have any questions?


Here are 5 questions that expand on this concept:

  1. How can you convert other explicit formulas into recursive formulas?
  2. What is the advantage of using a recursive formula instead of an explicit one?
  3. How would you derive a closed-form expression from a recursive formula?
  4. Can you graph this sequence to visualize its growth?
  5. How does the rate of change in this sequence compare to other arithmetic progressions?

Tip: When writing recursive formulas, always include the base case, as it defines the starting point for the recursion!

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Math Problem Analysis

Mathematical Concepts

Algebra
Arithmetic Sequences
Recursive Formulas

Formulas

Explicit formula: a_n = 4 + (n-1) * 6
Recursive formula: a_n = a_(n-1) + 6 for n ≥ 2, with a_1 = 4

Theorems

Arithmetic progression properties

Suitable Grade Level

Grades 8-10