Math Problem Statement

  1. For each of these sequences find a recurrence relation satisfied by this sequence. (The answers are not unique because there are infinitely many different recurrence relations satisfied by any sequence .) a) a_{n} = 3 b) a_{n} = 2n; a_{n} = 2n + 3 d) a_{n} = 5 ^ n e) a_{n} = n ^ 2 f) a_{n} = n ^ 2 + n g) a_{n} = n + (- 1) ^ n h ) a_{n} = n! )

Solution

Let's find recurrence relations for each of the given sequences. A recurrence relation expresses each term of the sequence as a function of its preceding terms.


a) an=3a_n = 3

This is a constant sequence. Every term of the sequence is 3. Therefore, the simplest recurrence relation is: an=an1a_n = a_{n-1} with the initial condition a1=3a_1 = 3. Alternatively, we can also express it as: an=3a_n = 3


b) an=2na_n = 2n

This is an arithmetic sequence with a constant difference of 2 between consecutive terms. The recurrence relation is: an=an1+2a_n = a_{n-1} + 2 with the initial condition a1=2a_1 = 2.


c) an=2n+3a_n = 2n + 3

This is also an arithmetic sequence, but with a constant difference of 2 between consecutive terms. The recurrence relation is: an=an1+2a_n = a_{n-1} + 2 with the initial condition a1=5a_1 = 5.


d) an=5na_n = 5^n

This is a geometric sequence with a ratio of 5 between consecutive terms. The recurrence relation is: an=5an1a_n = 5 \cdot a_{n-1} with the initial condition a1=5a_1 = 5.


e) an=n2a_n = n^2

The difference between consecutive terms is increasing by 2 each time. The recurrence relation is: an=an1+2n1a_n = a_{n-1} + 2n - 1 with the initial condition a1=1a_1 = 1.


f) an=n2+na_n = n^2 + n

Here, we can break down the sequence as an=n(n+1)a_n = n(n + 1). The recurrence relation can be written as: an=an1+2na_n = a_{n-1} + 2n with the initial condition a1=2a_1 = 2.


g) an=n+(1)na_n = n + (-1)^n

This sequence alternates between adding and subtracting 1 to nn. The recurrence relation is: an=an1+2(1)na_n = a_{n-1} + 2(-1)^n with the initial condition a1=0a_1 = 0.


h) an=n!a_n = n!

The factorial sequence is defined by the product of all positive integers up to nn. The recurrence relation is: an=nan1a_n = n \cdot a_{n-1} with the initial condition a1=1a_1 = 1.


Would you like further clarification or additional details on any of these sequences?

Here are 5 related questions to expand on this topic:

  1. How can we derive a recurrence relation for a sequence that is neither arithmetic nor geometric?
  2. Can you explain how initial conditions affect the solution of a recurrence relation?
  3. What are homogeneous and non-homogeneous recurrence relations?
  4. How can recurrence relations be used to model real-world problems?
  5. Can generating functions be used to solve recurrence relations?

Tip: Understanding the pattern of differences between consecutive terms often helps in deriving the recurrence relation.

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Math Problem Analysis

Mathematical Concepts

Recurrence Relations
Arithmetic Sequences
Geometric Sequences
Factorial Function
Quadratic Sequences

Formulas

Recurrence Relation Formula: a_n = f(a_{n-1})
Arithmetic Sequence: a_n = a_{n-1} + d
Geometric Sequence: a_n = r * a_{n-1}
Factorial: a_n = n * a_{n-1}
Quadratic Sequence: a_n = a_{n-1} + 2n - 1

Theorems

Recurrence Relation Theorem
Arithmetic Sequence Theorem
Geometric Sequence Theorem

Suitable Grade Level

College Level