Given that the length of the rectangle is 3 times its width and the area of the rectangle is 243 square units, we can use the formula for the area of a rectangle:

$\text{Area} = \text{Length} \times \text{Width}$

Let's define:

• $w$ as the width of the rectangle.
• The length $L = 3w$ (since the length is 3 times the width).

Now, substitute the length and width into the area formula:

$243 = 3w \times w$

This simplifies to:

$243 = 3w^2$

Thus, the equation to find the width of the rectangle is:

$3w^2 = 243$

You can solve this equation for $w$ to find the width.

Do you want details on how to solve this equation or have any questions?

Here are 5 related questions:

1. What is the width of the rectangle if we solve the equation $3w^2 = 243$?
2. How do you calculate the perimeter of this rectangle?
3. If the area were doubled, how would the equation change?
4. Can the width be a non-integer value in this case?
5. What if the length were 4 times the width—how would the equation change?

Tip: Always check units when solving real-world geometry problems to avoid mistakes.