Math Problem Statement

Rectangle ABCD with AB = 6 and BC = 7 is inscribed in a semicircle such that CD lies on the diameter. If the area of the semicircle is a\pi , find a

Solution

We are given a rectangle ABCDABCD inscribed in a semicircle with diameter along CDCD. The dimensions of the rectangle are AB=6AB = 6 and BC=7BC = 7, where ABAB is the height of the rectangle and BCBC is one of the sides parallel to the diameter.

Step 1: Understanding the Geometry

  • The semicircle's diameter coincides with CDCD, so the diameter of the semicircle is equal to the length of CDCD.
  • The center of the semicircle is the midpoint of CDCD, and the radius of the semicircle is half the diameter.

Since the rectangle is inscribed in the semicircle, the diagonal of the rectangle ACAC must be the radius of the semicircle.

Step 2: Applying the Pythagorean Theorem

We can calculate the length of the diagonal ACAC using the Pythagorean theorem. The diagonal is the hypotenuse of a right triangle with legs AB=6AB = 6 and BC=7BC = 7.

AC=AB2+BC2=62+72=36+49=85AC = \sqrt{AB^2 + BC^2} = \sqrt{6^2 + 7^2} = \sqrt{36 + 49} = \sqrt{85}

Thus, the length of the diagonal ACAC is 85\sqrt{85}. Since the diagonal equals the radius of the semicircle, the radius of the semicircle is 85\sqrt{85}.

Step 3: Calculating the Area of the Semicircle

The formula for the area of a semicircle is:

Area of semicircle=12πr2\text{Area of semicircle} = \frac{1}{2} \pi r^2

Substitute r=85r = \sqrt{85} into the formula:

Area of semicircle=12π(85)2=12π85=852π\text{Area of semicircle} = \frac{1}{2} \pi (\sqrt{85})^2 = \frac{1}{2} \pi \cdot 85 = \frac{85}{2} \pi

Step 4: Solving for aa

We are told that the area of the semicircle is aπa\pi. From the above expression, we can see that:

a=852a = \frac{85}{2}

Thus, the value of aa is 852\boxed{\frac{85}{2}}.

Would you like more details on any specific part of this solution? Here are 5 related questions to explore further:

  1. How would the solution change if the rectangle had different dimensions?
  2. What is the relationship between the radius and the diagonal of the rectangle?
  3. Can you derive the formula for the area of a semicircle?
  4. How would this problem change if the figure were a full circle instead of a semicircle?
  5. What if the rectangle was rotated inside the semicircle?

Tip: The Pythagorean theorem is a powerful tool for finding relationships between the sides of right triangles, and it often comes up when working with geometric figures inscribed in circles.

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Math Problem Analysis

Mathematical Concepts

Geometry
Pythagorean Theorem
Area of a Semicircle

Formulas

Pythagorean theorem: AC = √(AB² + BC²)
Area of semicircle: (1/2) * π * r²

Theorems

Pythagorean Theorem

Suitable Grade Level

Grades 9-10