Math Problem Statement
Rectangle ABCD with AB = 6 and BC = 7 is inscribed in a semicircle such that CD lies on the diameter. If the area of the semicircle is a\pi , find a
30.2
29
27
18
116.5
32
28.5
27.5
Solution
We are given a rectangle inscribed in a semicircle, with the side lying on the diameter. The sides of the rectangle are and , and the area of the semicircle is . We need to find .
Step 1: Relating the Dimensions of the Rectangle to the Semicircle
Since lies on the diameter of the semicircle, the length of is the diameter of the semicircle. Using the Pythagorean theorem, we can find the diameter because is a rectangle, and the diagonal serves as the hypotenuse of a right triangle with sides and .
Thus, the diameter of the semicircle is .
Step 2: Finding the Radius of the Semicircle
The radius of the semicircle is half the diameter:
Step 3: Area of the Semicircle
The area of a semicircle is given by:
Substitute :
We are told that the area of the semicircle is , so we equate:
Step 4: Solving for
Divide both sides by :
Thus, the value of is approximately .
However, this value does not match any of the options given. Let's verify if rounding or other assumptions should be revisited. Based on this analysis, none of the listed options align perfectly with the calculated value.
Would you like more clarification, or should I look into an alternative approach? Here are 5 related questions for further exploration:
- What is the significance of the diagonal in a rectangle inscribed in a semicircle?
- How does the Pythagorean theorem help in determining the diameter of the semicircle?
- What is the geometric relationship between a rectangle and a semicircle?
- How can you derive the area formula for a semicircle?
- What other properties of inscribed figures can you explore mathematically?
Tip: Always verify if the precision required for a solution matches the given options.
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Math Problem Analysis
Mathematical Concepts
Geometry
Pythagorean Theorem
Area of a Semicircle
Formulas
Pythagorean Theorem: AC = √(AB² + BC²)
Radius of Semicircle: r = Diameter / 2
Area of Semicircle: (1/2)πr²
Theorems
Pythagorean Theorem
Suitable Grade Level
Grades 9-11
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