Math Problem Statement

Rectangle ABCD with AB = 6 and BC = 7 is inscribed in a semicircle such that CD lies on the diameter. If the area of the semicircle is a\pi , find a

30.2

29

27

18

116.5

32

28.5

27.5

Solution

We are given a rectangle ABCDABCD inscribed in a semicircle, with the side CDCD lying on the diameter. The sides of the rectangle are AB=6AB = 6 and BC=7BC = 7, and the area of the semicircle is aπa\pi. We need to find aa.

Step 1: Relating the Dimensions of the Rectangle to the Semicircle

Since CDCD lies on the diameter of the semicircle, the length of CDCD is the diameter of the semicircle. Using the Pythagorean theorem, we can find the diameter because ABCDABCD is a rectangle, and the diagonal ACAC serves as the hypotenuse of a right triangle with sides ABAB and BCBC.

AC=AB2+BC2=62+72=36+49=85AC = \sqrt{AB^2 + BC^2} = \sqrt{6^2 + 7^2} = \sqrt{36 + 49} = \sqrt{85}

Thus, the diameter of the semicircle is 85\sqrt{85}.

Step 2: Finding the Radius of the Semicircle

The radius of the semicircle is half the diameter:

r=852r = \frac{\sqrt{85}}{2}

Step 3: Area of the Semicircle

The area of a semicircle is given by:

Area of semicircle=12πr2\text{Area of semicircle} = \frac{1}{2} \pi r^2

Substitute r=852r = \frac{\sqrt{85}}{2}:

Area of semicircle=12π(852)2=12π854=85π8\text{Area of semicircle} = \frac{1}{2} \pi \left(\frac{\sqrt{85}}{2}\right)^2 = \frac{1}{2} \pi \frac{85}{4} = \frac{85\pi}{8}

We are told that the area of the semicircle is aπa\pi, so we equate:

85π8=aπ\frac{85\pi}{8} = a\pi

Step 4: Solving for aa

Divide both sides by π\pi:

858=a\frac{85}{8} = a

a=10.625a = 10.625

Thus, the value of aa is approximately 10.62510.625.

However, this value does not match any of the options given. Let's verify if rounding or other assumptions should be revisited. Based on this analysis, none of the listed options align perfectly with the calculated value.

Would you like more clarification, or should I look into an alternative approach? Here are 5 related questions for further exploration:

  1. What is the significance of the diagonal in a rectangle inscribed in a semicircle?
  2. How does the Pythagorean theorem help in determining the diameter of the semicircle?
  3. What is the geometric relationship between a rectangle and a semicircle?
  4. How can you derive the area formula for a semicircle?
  5. What other properties of inscribed figures can you explore mathematically?

Tip: Always verify if the precision required for a solution matches the given options.

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Math Problem Analysis

Mathematical Concepts

Geometry
Pythagorean Theorem
Area of a Semicircle

Formulas

Pythagorean Theorem: AC = √(AB² + BC²)
Radius of Semicircle: r = Diameter / 2
Area of Semicircle: (1/2)πr²

Theorems

Pythagorean Theorem

Suitable Grade Level

Grades 9-11