Math Problem Statement
For the function f(x), find the maximum number of real zeros, the maximum number of x-intercepts, and the maximum number of turning points that the function can have. f\left(x\right)=x^{7}-x^{2}+8
Solution
Given the function , let’s determine the following properties:
1. Maximum Number of Real Zeros
The maximum number of real zeros of a polynomial is equal to its degree. Here, the degree of is (the highest power of ). Therefore, the maximum number of real zeros is:
2. Maximum Number of -Intercepts
The -intercepts of a function are the points where . Since real zeros correspond to -intercepts, the maximum number of -intercepts is also:
3. Maximum Number of Turning Points
The maximum number of turning points of a polynomial function is given by , where is the degree of the polynomial. For , the degree is , so the maximum number of turning points is:
Summary
- Maximum number of real zeros:
- Maximum number of -intercepts:
- Maximum number of turning points:
Would you like further details on any of these concepts?
Here are some related questions for further exploration:
- How do you determine the possible number of complex roots for a polynomial?
- Why is the maximum number of turning points always one less than the degree of the polynomial?
- How do we find the actual turning points of a polynomial function?
- Can a polynomial with an odd degree ever have no real zeros?
- How can the behavior of the end terms affect the shape of the polynomial graph?
Tip: Remember, a polynomial function of degree has at most real zeros, but it may have fewer depending on the nature of its roots.
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Math Problem Analysis
Mathematical Concepts
Polynomial Functions
Zeros of Polynomials
Turning Points
Intercepts
Formulas
The maximum number of real zeros of a polynomial is equal to its degree
The maximum number of turning points of a polynomial function is n - 1, where n is the degree of the polynomial
Theorems
Fundamental Theorem of Algebra
Suitable Grade Level
Grades 10-12
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