Math Problem Statement

real life situation arithmetic sequence

Solution

Arithmetic sequences commonly appear in real-life situations, where there is a consistent pattern of growth or decline. Here are a few examples of arithmetic sequences in daily life:

  1. Saving Money Over Time: Suppose you save $50 every month. The total amount saved over time forms an arithmetic sequence where the common difference is $50.

    • Month 1: $50
    • Month 2: $100
    • Month 3: $150
    • and so on...
  2. Filling a Water Tank: Imagine you are filling a water tank with 5 liters of water every minute. The total volume of water in the tank over time forms an arithmetic sequence, where the common difference is 5 liters.

    • Minute 1: 5 liters
    • Minute 2: 10 liters
    • Minute 3: 15 liters
    • and so on...
  3. Daily Step Count Increase: Suppose you want to increase the number of steps you take each day by 500. Over time, your step count forms an arithmetic sequence:

    • Day 1: 2000 steps
    • Day 2: 2500 steps
    • Day 3: 3000 steps
    • and so on...
  4. Staircase Construction: The height of each step in a staircase is usually uniform. If each step is 15 cm, the cumulative height you ascend forms an arithmetic sequence.

    • Step 1: 15 cm
    • Step 2: 30 cm
    • Step 3: 45 cm
    • and so on...
  5. Car Depreciation: A car's value depreciates by a fixed amount each year. If a car's value decreases by $2000 per year, the value of the car over time follows an arithmetic sequence.

    • Year 1: $20,000
    • Year 2: $18,000
    • Year 3: $16,000
    • and so on...

In all of these examples, the core idea of an arithmetic sequence is the constant increase or decrease by a fixed amount, which is the common difference.

Example Calculation:

If you save $50 every month, the arithmetic sequence is:

  • First term: a=50a = 50
  • Common difference: d=50d = 50
  • To find how much you save after 12 months, use the formula for the nn-th term of an arithmetic sequence: an=a+(n1)da_n = a + (n-1) \cdot d a12=50+(121)50=50+550=600a_{12} = 50 + (12-1) \cdot 50 = 50 + 550 = 600 After 12 months, you would have saved $600.

Would you like more details on this or have any questions?

Further Questions:

  1. How can you use arithmetic sequences to model mortgage payments or loans?
  2. Can an arithmetic sequence be used to plan for a project timeline with regular intervals?
  3. What is the significance of the common difference in real-world applications?
  4. How do you find the sum of an arithmetic sequence, such as for cumulative savings?
  5. What happens if the common difference in an arithmetic sequence is negative?

Tip: To find the sum of an arithmetic sequence over time, use the formula: Sn=n2(2a+(n1)d)S_n = \frac{n}{2} \cdot (2a + (n-1) \cdot d) This helps calculate total savings or project progress!

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Math Problem Analysis

Mathematical Concepts

Arithmetic Sequences
Linear Growth
Constant Differences

Formulas

nth term of an arithmetic sequence: a_n = a + (n-1) * d
Sum of an arithmetic sequence: S_n = (n / 2) * (2a + (n-1) * d)

Theorems

Arithmetic sequence formula

Suitable Grade Level

Grades 6-10