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The problem provided contains a comparison of money owned by Andi, Budi, and Candra, along with a few statements to be verified. Let’s break down the information:

1. **Ratio of Andi and Budi’s money**: \( 2 : 5 \)
2. **Ratio of Budi and Candra’s money**: \( 3 : 4 \)
3. **Total money they have together**: Rp 1,230,000.
4. After redistribution, the new ratio between Andi, Budi, and Candra becomes \( 1 : 2 : 3 \).

To solve this, we need to find how much money each person initially had and how much they had after redistribution.

### Step-by-Step Approach:

#### 1. Express ratios in terms of a common variable
- The ratio of Andi to Budi is \( 2 : 5 \), which means if Andi has 2x, then Budi has 5x.
- The ratio of Budi to Candra is \( 3 : 4 \), which means if Budi has 3y, then Candra has 4y.

#### 2. Equating the two Budi values
Since Budi appears in both ratios, we can equate the two expressions for Budi’s amount:

\[
5x = 3y
\]
This implies \( y = \frac{5x}{3} \).

#### 3. Find the total money in terms of x
Using the ratios of Andi, Budi, and Candra, the total amount is:

\[
\text{Total} = 2x + 5x + 4y
\]

Substitute \( y = \frac{5x}{3} \):

\[
\text{Total} = 2x + 5x + 4\left(\frac{5x}{3}\right)
\]

Simplifying:

\[
\text{Total} = 7x + \frac{20x}{3} = \frac{21x}{3} + \frac{20x}{3} = \frac{41x}{3}
\]

We know the total money is Rp 1,230,000, so:

\[
\frac{41x}{3} = 1,230,000
\]

Solving for x:

\[
41x = 3,690,000
\]
\[
x = \frac{3,690,000}{41} = 90,000
\]

#### 4. Find individual amounts before redistribution
- Andi’s amount = \( 2x = 2(90,000) = 180,000 \)
- Budi’s amount = \( 5x = 5(90,000) = 450,000 \)
- Candra’s amount = \( 4y = 4\left(\frac{5x}{3}\right) = \frac{20x}{3} = \frac{20(90,000)}{3} = 600,000 \)

So, Andi had Rp 180,000, Budi had Rp 450,000, and Candra had Rp 600,000.

#### 5. After redistribution, the new ratio is \( 1 : 2 : 3 \)
- Total money: Rp 1,230,000
- Let Andi have z, Budi have 2z, and Candra have 3z. Then:

\[
z + 2z + 3z = 1,230,000
\]
\[
6z = 1,230,000
\]
\[
z = 205,000
\]

So, after redistribution:
- Andi has Rp 205,000
- Budi has \( 2 \times 205,000 = 410,000 \)
- Candra has \( 3 \times 205,000 = 615,000 \)

#### Verification of Statements:
1. **Budi gave Rp 25,000 to Andi and Rp 15,000 to Candra**:
   - Before: Budi had Rp 450,000, Andi had Rp 180,000, and Candra had Rp 600,000.
   - After redistribution: Andi had Rp 205,000, Candra had Rp 615,000, and Budi had Rp 410,000.
   - Thus, Budi gave Rp 25,000 to Andi and Rp 15,000 to Candra, making this statement **True**.

2. **Candra’s money before redistribution was Rp 600,000**:
   - This is **True**.

Let me know if you need more details or have any other questions.

### Related Questions:
1. How do you solve ratio problems with more than two participants?
2. How would the problem change if the total amount was different?
3. What happens if the ratio changes after redistribution?
4. Can you represent this problem using algebraic equations?
5. How can you check if your answer is correct in ratio problems?

#### Tip:
Always check if the ratios add up to the total when solving problems involving multiple participants.

Perbandingan uang Andi dan Budi adalah 2 : 5, sedangkan perbandingan uang Budi dan Candra adalah 3 : 4. Jumlah uang mereka bertiga adalah Rp 1.230.000. Mereka sepakat membagi uang mereka, sehingga perbandingan uang Andi : Budi : Candra menjadi 1 : 2 : 3. Tentukan apakah pernyataan berikut benar: Budi memberikan sebagian uang kepada Andi dan Candra masing-masing Rp25.000 dan Rp15.000. Uang Candra sebelum dibagikan sebesar Rp600.000.

Learn how to solve a ratio problem involving Andi, Budi, and Candra's money, where their total sum is Rp 1,230,000, and the ratio changes after redistribution. Understand how Budi gives Rp 25,000 to Andi and Rp 15,000 to Candra.

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