Math Problem Statement
The volume of a cantaloupe with radius r is given by .V =
-r. The radius is
growing at a at a rate of 0.2 cm/week, at a time when the radius is 8.6 cm. How fast is the volume changing at that moment? Round your answer to 2 decimal places.
Solution
It seems like the volume equation for the cantaloupe is incomplete in your query. However, I assume the volume is modeled as a sphere, so the volume formula would likely be:
Where:
- is the volume,
- is the radius of the cantaloupe,
- and is a constant.
We are given that the radius is increasing at a rate of , and at the moment of interest, the radius .
To find how fast the volume is changing at that moment, we need to compute the rate of change of the volume . We can do this using related rates.
Step 1: Differentiate the volume equation
We begin by differentiating the volume formula with respect to time using the
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Math Problem Analysis
Mathematical Concepts
Calculus
Related Rates
Derivatives
Formulas
V = (4/3)πr^3
dV/dt = 4πr^2(dr/dt)
Theorems
Chain Rule
Suitable Grade Level
Grades 11-12
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