Math Problem Statement

The temperature in a city is modeled by the linear equation T(t)=5t+20T(t)=5t+20, where T(t)T(t) is the temperature in degrees Celsius and tt is the time in hours. What is the rate of change of temperature per hour?

A) 5°C per hour

B) 20°C per hour

C) 25°C per hour

D) 50°C per hour

Solution

To find the rate of change of temperature per hour, we need to determine the derivative of the temperature equation T(t)=5t+20T(t) = 5t + 20 with respect to time tt.

The derivative of T(t)T(t) with respect to tt is:

dTdt=5\frac{dT}{dt} = 5

This represents the rate of change of temperature per hour.

Thus, the rate of change of temperature is 5°C per hour.

The correct answer is A) 5°C per hour.

Would you like more details or have any questions? Here are some related questions for you:

  1. How do derivatives relate to rates of change?
  2. What is the physical significance of the slope of a linear equation?
  3. Can the rate of change be negative in certain cases?
  4. How would you calculate the rate of change for a non-linear equation?
  5. What is the unit of measurement for a rate of change?

Tip: In many real-world scenarios, the rate of change is represented by the slope of the function.

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Math Problem Analysis

Mathematical Concepts

Linear equations
Rate of change
Derivatives

Formulas

T(t) = 5t + 20
Rate of change = derivative of T(t) with respect to t

Theorems

Linear rate of change theorem (slope of a linear function)

Suitable Grade Level

Grades 9-10