Math Problem Statement

Can you do all the steps and show the work please

Find the change in temperature, ΔT, between t=1 and t=2 min, given that the rate of change of temperature is T'(t) = (4t - 2)e^{t^2 - t} °C/min.

Solution

The given problem provides the rate of change of temperature T(t)T'(t) as a function of time tt:

T(t)=(4t2)et2tT'(t) = (4t - 2)e^{t^2 - t}

We are asked to find the change in temperature, ΔT\Delta T, between t=1t = 1 minute and t=2t = 2 minutes. The change in temperature ΔT\Delta T is given by the integral of the rate of change of temperature:

ΔT=12T(t)dt\Delta T = \int_{1}^{2} T'(t) \, dt

Step 1: Set up the integral

The integral we need to solve is:

ΔT=12(4t2)et2tdt\Delta T = \int_{1}^{2} (4t - 2)e^{t^2 - t} \, dt

Step 2: Use substitution method

To solve this integral, we can use substitution. Let:

u=t2tu = t^2 - t

Then, differentiate uu with respect to tt:

dudt=2t1\frac{du}{dt} = 2t - 1 or equivalently: du=(2t1)dtdu = (2t - 1) \, dt

Now, we need to express (4t2)dt(4t - 2) \, dt in terms of dudu. Notice that:

4t2=2(2t1)4t - 2 = 2(2t - 1)

So, we can rewrite the integral as:

ΔT=122(2t1)et2tdt\Delta T = \int_{1}^{2} 2(2t - 1)e^{t^2 - t} \, dt

This simplifies using du=(2t1)dtdu = (2t - 1) \, dt:

ΔT=212eudu\Delta T = 2 \int_{1}^{2} e^{u} \, du

Step 3: Solve the integral

The integral of eue^u is straightforward:

eudu=eu\int e^u \, du = e^u

Now, we need to substitute back for u=t2tu = t^2 - t. Thus:

ΔT=2[et2t]12\Delta T = 2 \left[ e^{t^2 - t} \right]_{1}^{2}

Step 4: Evaluate the bounds

First, evaluate at t=2t = 2:

e(222)=e42=e2e^{(2^2 - 2)} = e^{4 - 2} = e^2

Next, evaluate at t=1t = 1:

e(121)=e11=e0=1e^{(1^2 - 1)} = e^{1 - 1} = e^0 = 1

Now, substitute these values into the expression for ΔT\Delta T:

ΔT=2(e21)\Delta T = 2 \left( e^2 - 1 \right)

Step 5: Final Answer

Therefore, the change in temperature between t=1t = 1 and t=2t = 2 minutes is:

ΔT=2(e21)2(7.3891)=2×6.389=12.778°C\Delta T = 2 \left( e^2 - 1 \right) \approx 2 \left( 7.389 - 1 \right) = 2 \times 6.389 = 12.778 \, \text{°C}

Conclusion

The change in temperature ΔT\Delta T between t=1t = 1 minute and t=2t = 2 minutes is approximately 12.778°C12.778 \, \text{°C}.


Do you want further details on any step or have any questions?

Here are 5 related questions to consider:

  1. How do you choose a substitution for solving integrals?
  2. What is the significance of the exponential function in the rate of change?
  3. Can this method be applied to any rate of change problem?
  4. How would the result change if the bounds were different, say from t=0t = 0 to t=3t = 3?
  5. Why does solving integrals help in finding the total change of a quantity?

Tip: Always check whether substitution or integration by parts is the best method for complex integrals like this one!

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Math Problem Analysis

Mathematical Concepts

Calculus
Integration
Exponential Functions

Formulas

T'(t) = (4t - 2)e^{t^2 - t}
ΔT = ∫ T'(t) dt from t=1 to t=2

Theorems

Fundamental Theorem of Calculus
Substitution in Integration

Suitable Grade Level

Undergraduate Calculus