Math Problem Statement
Solution
This optimization problem requires determining the shortest time for the rancher to travel from his ranch to the city using two distinct travel speeds: 40 mph across the open range and 50 mph along the highway.
Let's break this down step by step:
Variables and Equations:
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Diagram Information:
- Distance across the range: Hypotenuse of a triangle with legs of 20 miles (north-south) and miles (east-west).
- Distance along the highway: , where is the portion of the eastward highway covered by traveling across the range.
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Travel Speeds:
- Across the range: 40 mph
- Along the highway: 50 mph
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Objective: Minimize total travel time , which is the sum of the time taken across the range and along the highway.
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Distance Across the Range: The hypotenuse is given by:
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Time Across the Range:
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Time Along the Highway:
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Total Time:
Optimization:
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Minimize : Take the derivative of and solve for where .
Simplify:
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Set :
Multiply through by :
Square both sides:
Expand:
Solve for :
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Interpretation:
- The rancher should travel approximately 26.68 miles east across the open range before switching to the highway.
Total Time:
Substitute into to find the minimum travel time:
This completes the solution process. Let me know if you’d like further explanation or calculations!
Related Questions:
- How does the travel time vary if the highway speed increases to 60 mph?
- What happens if the rancher takes a direct diagonal path to the city?
- How would the calculation change if the open-range speed decreases to 30 mph?
- What optimization techniques could be used to confirm the solution?
- Could this problem be solved graphically instead of algebraically?
Tip:
Always visualize the geometry of optimization problems to better understand the variables and constraints involved.
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Math Problem Analysis
Mathematical Concepts
Optimization
Geometry
Calculus
Formulas
Distance = Speed × Time
Hypotenuse: c = √(a² + b²)
Derivative for critical points: T'(x) = 0
Theorems
Pythagorean Theorem
First Derivative Test
Suitable Grade Level
Grades 11-12 or College Level
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