Math Problem Statement
Prove that there are either 6 mathematicians such that no two were asleep at the same time, or 6 mathematicians such that there was some point in time during which all 6 were asleep.
Solution
To prove this statement, we can use the pigeonhole principle. The statement essentially requires us to show that for a group of mathematicians, there exists either:
- A set of six mathematicians, none of whom were asleep at the same time, or
- A set of six mathematicians who were all asleep simultaneously at some point in time.
This is a variation of Ramsey Theory applied to two types of configurations within a group. Specifically, this is related to Ramsey Number , which means that any graph with 36 vertices will contain either a complete subgraph or an independent set . Here’s the detailed proof:
Proof:
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Interpretation in Graph Theory:
- Consider each mathematician as a vertex in a graph.
- Draw an edge between two vertices if the two mathematicians were not asleep at the same time.
- No edge between two vertices means that these two mathematicians were asleep simultaneously at some point.
- We are asked to find either a set of 6 vertices where all pairs are connected (a , where no two were asleep at the same time) or a set of 6 vertices with no connections between them (an independent set , where all were asleep at the same time).
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Using the Pigeonhole Principle with Ramsey Numbers:
- For any two-colored complete graph with 36 vertices, the Ramsey number tells us that there will always be either a or an subgraph.
- This means, within a group of 36 mathematicians, there must either exist a set of 6 who were never asleep at the same time (no edge between them, forming a ) or a set of 6 mathematicians who were all asleep at some point (an ).
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Conclusion:
- Since the minimum required number of mathematicians to guarantee either situation is 36, any group of 36 mathematicians will meet the conditions of either a or an .
- Therefore, within any group of 36 mathematicians, there will necessarily exist either:
- A group of 6 mathematicians who were never asleep at the same time, or
- A group of 6 mathematicians who were all asleep at the same time.
This satisfies the conditions of the statement, thus proving that such a configuration always exists for a group of 36 mathematicians.
Would you like more details on any specific part of this proof?
Related Questions:
- What is the pigeonhole principle, and how is it used in combinatorics?
- How does Ramsey Theory apply to real-world scenarios?
- What are other applications of Ramsey numbers beyond graph theory?
- Can the proof above be generalized for other numbers, like proving ?
- How does the concept of independent sets work in graph theory?
Tip: Understanding the pigeonhole principle can simplify complex proofs, especially in combinatorics and probability.
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Math Problem Analysis
Mathematical Concepts
Ramsey Theory
Graph Theory
Pigeonhole Principle
Combinatorics
Formulas
Ramsey Number R(6, 6) = 36
Theorems
Ramsey Theorem
Pigeonhole Principle
Suitable Grade Level
University Level (Advanced Undergraduate/Graduate)
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