Math Problem Statement

Determine the radius of convergence, R, of the series ∑ (x^n / (6^n * n^3)).

Solution

To find the radius of convergence, RR, of the given series:

n=1xn6nn3,\sum_{n=1}^\infty \frac{x^n}{6^n n^3},

we apply the ratio test. The ratio test for convergence requires computing the ratio:

limnan+1an,\lim_{n \to \infty} \left| \frac{a_{n+1}}{a_n} \right|,

where an=xn6nn3a_n = \frac{x^n}{6^n n^3}.


Step-by-Step Solution:

  1. Define ana_n: an=xn6nn3.a_n = \frac{x^n}{6^n n^3}.

  2. Compute an+1a_{n+1}: Replace nn with n+1n+1 in ana_n: an+1=xn+16n+1(n+1)3.a_{n+1} = \frac{x^{n+1}}{6^{n+1} (n+1)^3}.

  3. Calculate the ratio an+1an\frac{a_{n+1}}{a_n}: an+1an=xn+16n+1(n+1)3xn6nn3.\frac{a_{n+1}}{a_n} = \frac{\frac{x^{n+1}}{6^{n+1} (n+1)^3}}{\frac{x^n}{6^n n^3}}.

    Simplify the terms: an+1an=xn+16n+1(n+1)36nn3xn.\frac{a_{n+1}}{a_n} = \frac{x^{n+1}}{6^{n+1} (n+1)^3} \cdot \frac{6^n n^3}{x^n}.

    Separate the powers of xx, 66, and nn: an+1an=xxn66nn3(n+1)3.\frac{a_{n+1}}{a_n} = \frac{x \cdot x^n}{6 \cdot 6^n} \cdot \frac{n^3}{(n+1)^3}.

    an+1an=x6n3(n+1)3.\frac{a_{n+1}}{a_n} = \frac{|x|}{6} \cdot \frac{n^3}{(n+1)^3}.

  4. Take the limit as nn \to \infty: Focus on the term n3(n+1)3\frac{n^3}{(n+1)^3}: limnn3(n+1)3=limn(nn+1)3=limn(11n+1)3=1.\lim_{n \to \infty} \frac{n^3}{(n+1)^3} = \lim_{n \to \infty} \left( \frac{n}{n+1} \right)^3 = \lim_{n \to \infty} \left( 1 - \frac{1}{n+1} \right)^3 = 1.

    So the ratio becomes: limnan+1an=x6.\lim_{n \to \infty} \left| \frac{a_{n+1}}{a_n} \right| = \frac{|x|}{6}.

  5. Apply the ratio test for convergence: For the series to converge, the ratio must satisfy: x6<1    x<6.\frac{|x|}{6} < 1 \implies |x| < 6.

  6. Radius of Convergence: The radius of convergence RR is: R=6.R = 6.


Final Answer:

The radius of convergence is: R=6.\boxed{R = 6}.


Do you want a detailed explanation of the ratio test, or help with a follow-up concept?


Questions to Explore Further:

  1. How does the ratio test determine absolute convergence of a series?
  2. What happens when the radius of convergence is infinite?
  3. How do you apply the root test to find the radius of convergence?
  4. What is the interval of convergence, and how does it differ from the radius of convergence?
  5. Can the radius of convergence change if the series has additional terms (like factorials)?

Tip:

When applying the ratio test, always carefully handle factorials, powers, or other growth-related terms in the series to simplify correctly.

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Math Problem Analysis

Mathematical Concepts

Series
Radius of Convergence
Ratio Test

Formulas

Ratio Test: lim (n→∞) |a_(n+1) / a_n|
Radius of Convergence: |x| < R

Theorems

Ratio Test for Absolute Convergence

Suitable Grade Level

Undergraduate (Calculus II)