Math Problem Statement

Amery recorded the height and distance of a basketball when shooting a free throw, and you need to choose the quadratic equation for the function. Then, use the equation to find the approximate maximum height of the basketball.

Solution

The question asks you to select the correct quadratic equation that models the height of a basketball based on the given table of distance and height. Then, you need to use the equation to find the maximum height of the basketball.

Table:

  • Distance (x) in feet: 0, 2, 6, 9, 12, 13, 15
  • Height (f(x)) in feet: 4, 8.4, 12.1, 13.2, 12, 10.5, 9.8

You are provided with two quadratic equations to choose from:

  1. f(x)=0.118x2+2.112x+4.215f(x) = -0.118x^2 + 2.112x + 4.215
  2. f(x)=0.117x2+2.112x+4.215f(x) = -0.117x^2 + 2.112x + 4.215

To determine the maximum height of the basketball, we need to find the vertex of the quadratic function. The vertex of a parabola f(x)=ax2+bx+cf(x) = ax^2 + bx + c can be found using the formula for the x-coordinate of the vertex: x=b2ax = -\frac{b}{2a} This will give us the distance at which the maximum height occurs. After finding this x-value, we substitute it into the equation to find the corresponding height.

Step-by-Step Process:

  1. Identify the coefficients:

    • a=0.118a = -0.118 or 0.117-0.117
    • b=2.112b = 2.112
  2. Find the vertex for both options: x=2.1122×0.118=8.949 feet (for the first equation)x = -\frac{2.112}{2 \times -0.118} = 8.949 \text{ feet (for the first equation)} x=2.1122×0.117=9.02 feet (for the second equation)x = -\frac{2.112}{2 \times -0.117} = 9.02 \text{ feet (for the second equation)}

  3. Substitute the x-value back into the equation: Using the first equation, substitute x=8.949x = 8.949: f(8.949)=0.118(8.949)2+2.112(8.949)+4.215f(8.949) = -0.118(8.949)^2 + 2.112(8.949) + 4.215 The approximate height will be 13.665 feet.

Thus, the correct equation is f(x)=0.118x2+2.112x+4.215f(x) = -0.118x^2 + 2.112x + 4.215 and the maximum height is approximately 13.665 feet.

Would you like further details on any step or have any questions?

Relative Questions:

  1. How do you determine the vertex of any quadratic function?
  2. What role does the sign of the leading coefficient play in determining the shape of a parabola?
  3. Why is the vertex important when analyzing quadratic functions in real-world contexts?
  4. How can you verify that your solution is correct by graphing?
  5. Can quadratic regression be used to derive the same equation from the data?

Tip: The x-coordinate of the vertex of a quadratic function is always the point where the maximum or minimum value occurs, depending on whether the parabola opens downwards or upwards.

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Math Problem Analysis

Mathematical Concepts

Quadratic Functions
Algebra
Maximum of a Parabola

Formulas

Quadratic equation: ax^2 + bx + c
Vertex formula: x = -b / (2a)

Theorems

Vertex Theorem for Parabolas
Properties of Quadratic Functions

Suitable Grade Level

Grades 9-12